मराठी
Karnataka Board PUCPUC Science 2nd PUC Class 12

Expressing Concentration of Solutions

Advertisements

Topics

Estimated time: 4 minutes
CBSE: Class 12

Formula: Molarity

\[\mathrm{Molarity}=\frac{\text{Number of moles of solute}}{\text{Volume of solution in litres}}\]

\[=\frac{w}{\mathrm{Molar~Mass}}\times\frac{1000}{V}\]

CBSE: Class 12

Formula: Normality

\[\mathrm{Normality}=\frac{\text{Number of gram equivalents of solute}}{\text{Volume of solution of litres}}\]

Normality of a solution = Molarity × nf

CBSE: Class 12

Formula: Molality

\[\mathrm{Molality~}=\frac{\text{Number of moles of solute}}{\text{Mass of solvent in kg}}=\frac{W_{\mathrm{B}}}{M_{\mathrm{B}}}\times\frac{1000}{W_{\mathrm{A}}}\]

where A = solvent, B = solute

CBSE: Class 12

Definition: Mole Fraction

Mole fraction of a constituent is the fraction obtained by dividing the number of moles of that constituent by the total number of moles of all the constituents present in the solution.

\[x_{1}=\frac{n_{1}}{n_{1}+n_{2}+n_{3}+...+n_{i}}\]

Shaalaa.com | Solutions part 3 (Mass, volume percentage,Part per million)

Shaalaa.com


Next video


Shaalaa.com


Solutions part 3 (Mass, volume percentage,Part per million) [00:16:23]
S
Advertisements
Share
Notifications

Englishहिंदीमराठी


      Forgot password?
Use app×