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Reactions of Haloalkanes - Elimination Reactions

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Estimated time: 4 minutes
CBSE: Class 12

Key Points: Reactions of Haloalkanes — Elimination Reactions

β-Elimination Reaction:

  • When alkyl halides are heated with alcoholic KOH or KNH₂, they undergo β-elimination of HX to form an alkene (new π bond).
  • The carbon directly attached to X = α-carbon; the carbon adjacent to it = β-carbon.
  • Order of reactivity in elimination: R–Cl < R–Br < R–I

Saytzeff's Rule (Zaitsev's Rule):

  • In unsymmetrical alkyl halides, hydrogen is preferentially eliminated from the β-carbon with fewer hydrogen atoms → forms the more highly substituted alkene (major product).
  • e.g., 2-bromopentane → pent-2-ene (81%) [major] + pent-1-ene (19%) [minor]

Types of Elimination:

  1. α-elimination: Atom or group lost from the same carbon (gives carbene intermediates).
  2. β-elimination: H from β-carbon, X from α-carbon → alkene.
  • E₁ reaction: Two steps (similar mechanism to SN1)
  • E₂ reaction: One step (concerted, anti-periplanar geometry required — similar to SN2 but gives alkene)

Dehydrohalogenation:

  • Loss of HX from alkyl halide with alc. KOH → alkene.

\[\ce{\underset{Alky halide}{C_{n}H_{2n + 1}X} ->[Alcholic KOH] \underset{Alkene}{C_{n}H_{2n}} + KX + H2O}\]

  • With NaOH, Con. NH₃, t-BuONa, KNH₂, NaNH₂: elimination also occurs.

Shaalaa.com | Haloalkanes and Haloarenes part 22 (Elimination reaction, E1)

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Haloalkanes and Haloarenes part 22 (Elimination reaction, E1) [00:14:11]
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