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कर्नाटक बोर्ड पी.यू.सी.पीयूसी विज्ञान 2nd PUC Class 12

Nalorphene (C19H21NO3), similar to morphine, is used to combat withdrawal symptoms in narcotic users. Dose of nalorphene generally given is 1.5 mg. Calculate the mass of 1.5 × 10−3 m aqueous solution - Chemistry

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प्रश्न

Nalorphene (C19H21NO3), similar to morphine, is used to combat withdrawal symptoms in narcotic users. Dose of nalorphene generally given is 1.5 mg. Calculate the mass of 1.5 × 10−3 m aqueous solution required for the above dose.

संख्यात्मक
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उत्तर

Given, m = 1.5 × 10−3

The molar mass of nalorphene (C19H21NO3) is given as

= 19 × 12 + 21 × 1 + 1 × 14 + 3 × 16

= 311 g mol1

In 1.5 × 10−3 m aqueous solution of nalorphene,

1 kg (1000 g) of water contains 1.5 × 10−3 mol = 1.5 × 103 × 311 g

= 0.467 g

= 467 mg

Therefore, total mass of the solution = (1000 + 0.467) g

= 1000.467 g

Thus, for 467 mg of nalorphene, the solution required = 1000.467 g

Therefore, the mass of the solution containing 1.5 mg of nalorphene

= `1000.467/467 xx 1.5`

= 3.21 g

Hence, the mass of the aqueous solution required is 3.21 g.

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पाठ 1: Solutions - Exercises [पृष्ठ २९]

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एनसीईआरटी Chemistry Part 1 and 2 [English] Class 12
पाठ 1 Solutions
Exercises | Q 1.29 | पृष्ठ २९
नूतन Chemistry Part 1 and 2 [English] Class 12 ISC
पाठ 2 Solutions
'NCERT TEXT-BOOK' Exercises | Q 2.29 | पृष्ठ १२७

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