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Karnataka Board PUCPUC Science 2nd PUC Class 12

Nalorphene (C19H21NO3), similar to morphine, is used to combat withdrawal symptoms in narcotic users. Dose of nalorphene generally given is 1.5 mg. Calculate the mass of 1.5 × 10−3 m aqueous solution - Chemistry

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Question

Nalorphene (C19H21NO3), similar to morphine, is used to combat withdrawal symptoms in narcotic users. Dose of nalorphene generally given is 1.5 mg. Calculate the mass of 1.5 × 10−3 m aqueous solution required for the above dose.

Numerical
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Solution

Given, m = 1.5 × 10−3

The molar mass of nalorphene (C19H21NO3) is given as

= 19 × 12 + 21 × 1 + 1 × 14 + 3 × 16

= 311 g mol1

In 1.5 × 10−3 m aqueous solution of nalorphene,

1 kg (1000 g) of water contains 1.5 × 10−3 mol = 1.5 × 103 × 311 g

= 0.467 g

= 467 mg

Therefore, total mass of the solution = (1000 + 0.467) g

= 1000.467 g

Thus, for 467 mg of nalorphene, the solution required = 1000.467 g

Therefore, the mass of the solution containing 1.5 mg of nalorphene

= `1000.467/467 xx 1.5`

= 3.21 g

Hence, the mass of the aqueous solution required is 3.21 g.

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Chapter 1: Solutions - Exercises [Page 29]

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NCERT Chemistry Part 1 and 2 [English] Class 12
Chapter 1 Solutions
Exercises | Q 1.29 | Page 29

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