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Karnataka Board PUCPUC Science 2nd PUC Class 12

Nalorphene (C19H21NO3), similar to morphine, is used to combat withdrawal symptoms in narcotic users. Dose of nalorphene generally given is 1.5 mg. Calculate the mass of 1.5 × 10^−3 m aqueous solution

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Question

Nalorphene (C19H21NO3), similar to morphine, is used to combat withdrawal symptoms in narcotic users. Dose of nalorphene generally given is 1.5 mg. Calculate the mass of 1.5 × 10−3 m aqueous solution required for the above dose.

Numerical
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Solution

Given: m = 1.5 × 10−3

The molar mass of nalorphene (C19H21NO3) = 19 × 12 + 21 × 1 + 1 × 14 + 3 × 16

= 311 g mol1

In a 1.5 × 10−3 m aqueous solution of nalorphene,

1 kg (1000 g) of water contains 1.5 × 10−3 mol.

= 1.5 × 103 × 311 g

= 0.467 g

= 467 mg

∴ Total mass of the solution = (1000 + 0.467) g

= 1000.467 g

Thus, for 467 mg of nalorphene, the solution required is 1000.467 g.

∴ The mass of the solution containing 1.5 mg of nalorphene = `1000.467/467 xx 1.5`

= 3.21 g

Hence, the mass of the aqueous solution required is 3.21 g.

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Chapter 1: Solutions - 'NCERT TEXT-BOOK' Exercises [Page 127]

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Nootan Chemistry [English] Class 12 ISC
Chapter 1 Solutions
'NCERT TEXT-BOOK' Exercises | Q 2.29 | Page 127
NCERT Chemistry Part 1 and 2 [English] Class 12
Chapter 1 Solutions
Exercises | Q 1.29 | Page 29

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