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Karnataka Board PUCPUC Science 2nd PUC Class 12

Calculate the mass percentage of benzene (C6H6) and carbon tetrachloride (CCl4) if 22 g of benzene is dissolved in 122 g of carbon tetrachloride.

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Question

Calculate the mass percentage of benzene (C6H6) and carbon tetrachloride (CCl4) if 22 g of benzene is dissolved in 122 g of carbon tetrachloride.

Numerical
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Solution

Given: Mass of benzene = 22 g

Mass of carbon tetrachloride = 122 g

Mass of solution = Mass of benzene + Mass of carbon tetrachloride

= 22 + 122

= 144 g

Mass percentage of benzene = `"Mass of benzene"/"Mass of solution" xx 100`

= `22/144 xx 100`

= 15.28%

Mass percentage of carbon tetrachloride = `"Mass of carbon tetrachloride"/"Mass of solution" xx 100`

= `122/144 xx 100`

= 84.72%

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Chapter 1: Solutions - Intext Questions [Page 5]

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NCERT Chemistry Part 1 and 2 [English] Class 12
Chapter 1 Solutions
Intext Questions | Q 1.1 | Page 5

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