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कर्नाटक बोर्ड पी.यू.सी.पीयूसी विज्ञान 2nd PUC Class 12

Calculate the mass percentage of benzene (C6H6) and carbon tetrachloride (CCl4) if 22 g of benzene is dissolved in 122 g of carbon tetrachloride. - Chemistry

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प्रश्न

Calculate the mass percentage of benzene (C6H6) and carbon tetrachloride (CCl4) if 22 g of benzene is dissolved in 122 g of carbon tetrachloride.

संख्यात्मक
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उत्तर

Mass of solution = Mass of benzene + Mass of carbon tetrachloride

= 22 g + 122 g

= 144 g

Mass percentage of benzene = `"Mass of benzene"/"Mass of solution" xx 100`

= `(22  "g")/(144  "g") xx 100`

= 15.28%

Mass percentage of carbon tetrachloride = `"Mass of carbon tetrachloride"/"Mass of solution" xx 100`

= `(122  "g")/(144  "g") xx 100`

= 84.72%

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अध्याय 1: Solutions - Intext Questions [पृष्ठ ५]

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एनसीईआरटी Chemistry Part 1 and 2 [English] Class 12
अध्याय 1 Solutions
Intext Questions | Q 1.1 | पृष्ठ ५

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