Advertisements
Advertisements
प्रश्न
A 5% solution of \[\ce{Na2SO4.10H2O}\] (MW = 3 22) is isotonic with 2% solution of non- electrolytic, non volatile substance X. Find out the molecular weight of X.
Advertisements
उत्तर
π1 = π2
iC1RT = C2RT
`(3 xx 5)/322 = 2/"M"`
M = `(2 xx 322)/(3 xx 5)`
M = 42.9 g
APPEARS IN
संबंधित प्रश्न
Calculate the mole fraction of benzene in solution containing 30% by mass in carbon tetrachloride.
A sample of drinking water was found to be severely contaminated with chloroform (CHCl3) supposed to be a carcinogen. The level of contamination was 15 ppm (by mass):
- express this in percent by mass.
- determine the molality of chloroform in the water sample.
When a solute is present in trace quantities the following expression is used:
An aqueous solution of glucose is 10% in strength. The volume in which 1 g mole of it is dissolved, will be:
The volume of 4 N HCl and 10 N HCl required to make 1 litre of 6 N HCl are ____________.
200 ml of water is added to 500 ml of 0.2 M solution. What is the molarity of this diluted solution?
How many grams of concentrated nitric acid solution should be used to prepare 250 mL of 2.0M HNO3? The concentrated acid is 70% HNO3:
A solution made by dissolving 40 g NaOH in 1000 g of water is ____________.
4 L of 0.02 M aqueous solution of NaCl was diluted by adding one litre of water. The molality of the resultant solution is ______.
Match List-I with List-II:
| List-I | List-II |
| A. ppm | I. molL-¹ |
| B. Molarity | II. No units |
| C. Molality | III. Independent of temperature |
| D. Mole fraction | IV. Very dilute solutions |
Choose the correct answer from the options given below:
