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कर्नाटक बोर्ड पी.यू.सी.पीयूसी विज्ञान 2nd PUC Class 12

Calculate the mass of urea (NH2CONH2) required in making 2.5 kg of 0.25 molal aqueous solution - Chemistry

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प्रश्न

Calculate the mass of urea (NH2CONH2) required in making 2.5 kg of 0.25 molal aqueous solution.

संख्यात्मक
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उत्तर

Moles of urea = 0.25 mol

Mass of solvent (water) = 1 kg = 1000 g

Molar mass of urea (NH2CONH2) = 2(1 × 14 + 2 × 1) + 1 × 12 + 1 × 16

= 60 g mol−1

∴ Mass of urea in 1000 g of water = 0.25 mol × 60 g mol−1

= 15 g

Total mass of solution = 1000 + 15 g

= 1015 g

= 1.015 kg

Thus, 1.015 kg of solution contain urea = 15 g

∴ 2.5 kg of solution will require urea = `(15  "g")/(1.015  "kg") xx 2.5  "kg"`

= 36.95 g

= 37 g (approximately)

Hence, the mass of urea required is 37 g.

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पाठ 1: Solutions - Intext Questions [पृष्ठ ५]

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एनसीईआरटी Chemistry Part 1 and 2 [English] Class 12
पाठ 1 Solutions
Intext Questions | Q 1.4 | पृष्ठ ५

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