मराठी
कर्नाटक बोर्ड पी.यू.सी.पीयूसी विज्ञान 2nd PUC Class 12

Calculate the mole fraction of benzene in solution containing 30% by mass in carbon tetrachloride.

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प्रश्न

Calculate the mole fraction of benzene in solution containing 30% by mass in carbon tetrachloride.

संख्यात्मक
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उत्तर

Given: Mass of benzene in the solution = 30 g

Let the mass of the solution = 100 g

∴ Mass of carbon tetrachloride = (100 − 30) g

= 70 g

Molar mass of benzene (C6H6) = (6 × 12 + 6 × 1) g mol−1

= 78 g mol−1

∴ Number of moles of benzene (C6H6) = `"Mass"/"Molar mass"`

= `(30  "g")/(78  "g mol"^(−1))`

= 0.385 mol

Molar mass of carbon tetrachloride (CCl4) = 1 × 12 + 4 × 35.5

= 154 g mol−1

∴ Number of moles of CCl4 = `"Mass"/"Molar mass"`

= `(70  "g")/(154  "g mol"^(−1))`

= 0.455 mol

Mole fraction of benzene (C6H6) = `"Number of moles of benzene"/("Number of moles of benzene" + "Number of moles of Carbon tetrachloride")`

= `0.385/(0.385 + 0.455)`

= `0.385/0.84`

= 0.458

∴ Mole fraction of CCl4 = 1 − 0.458

= 0.542

∴ The mole fraction of benzene in a solution containing 30% by mass of carbon tetrachloride is 0.542.

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पाठ 1: Solutions - Intext Questions [पृष्ठ ५]

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एनसीईआरटी Chemistry Part 1 and 2 [English] Class 12
पाठ 1 Solutions
Intext Questions | Q 1.2 | पृष्ठ ५

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