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Question
Calculate the escape velocity on the surface of the moon given the mass and radius of the moon to be 7.34 × 1022 kg and 1.74 × 106 m respectively.
(Given: G = 6.67 × 10-11 Nm2/kg2)
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Solution
Given:
G = 6.67 × 10-11 Nm2/kg2
Mass of the moon = M = 7.34 × 1022 kg
The radius of the moon = R = 1.74 × 106.
Escape velocity = Vesc = `sqrt((2"GM")/"R")`
= `sqrt((2xx6.67xx10^-11xx7.34xx10^22)/(1.74xx10^6))`
= 2.37 km/s
The escape velocity on the moon is 2.37 km/s.
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