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Question
Calculate mean deviation from the median of the following data:
| Class interval: | 0–6 | 6–12 | 12–18 | 18–24 | 24–30 |
| Frequency | 4 | 5 | 3 | 6 | 2 |
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Solution
Calculation of mean deviation about the median.
| Class Interval | Mid-Values (xi) |
Frequency (fi) |
Cummulative Frequency (c.f.) |
\[\left| x_i - 14 \right|\]
|
\[f_i \left| x_i - 14 \right|\]
|
| 0–6 | 3 | 4 | 4 | 11 | 44 |
| 6–12 | 9 | 5 | 9 | 5 | 25 |
| 12–18 | 15 | 3 | 12 | 1 | 3 |
| 18–24 | 21 | 6 | 18 | 7 | 42 |
| 24–30 | 27 | 2 | 20 | 13 | 26 |
| N = 20 |
\[\sum f_i| x_i - 14 | = 140\]
|
Here, N = 20. So,
Mean deviation about median = \[\frac{1}{N}$\sum_{} f_i \left| x_i - 14 \right| = \frac{1}{20} \times 140 = 7\]
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