Question

Calculate the mean deviation from the mean for the  data:

(iv) 36, 72, 46, 42, 60, 45, 53, 46, 51, 49

 

Answer 1

Formula used for finding the mean deviation about the mean is given below: 

\[MD = \frac{1}{n} \sum^n_{i = 1} \left| d_i \right| , \text{ where } \left| d_i \right| = \left| x_i - x \right|\]

iv)
Let  x  be the mean of the given data.

\[x = \frac{36 + 746 + 42 + 60 + 45 + 53 + 46 + 51 + 59}{10} = 50\]

\[x_i\]	\[\left| d_i \right| = \left| x_i - \bar{x} \right|\]
36	14
72	22
46	4
42	8
60	10
45	5
53	3
46	4
51	1
49	1
Total	72

\[MD = \frac{1}{10} \times 72 = 7 . 2\]