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Question
Calculate the mean deviation from the mean for the data:
(iv) 36, 72, 46, 42, 60, 45, 53, 46, 51, 49
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Solution
Formula used for finding the mean deviation about the mean is given below:
\[MD = \frac{1}{n} \sum^n_{i = 1} \left| d_i \right| , \text{ where } \left| d_i \right| = \left| x_i - x \right|\]
iv)
Let x be the mean of the given data.
\[x = \frac{36 + 746 + 42 + 60 + 45 + 53 + 46 + 51 + 59}{10} = 50\]
|
|
|
| 36 | 14 |
| 72 | 22 |
| 46 | 4 |
| 42 | 8 |
| 60 | 10 |
| 45 | 5 |
| 53 | 3 |
| 46 | 4 |
| 51 | 1 |
| 49 | 1 |
| Total | 72 |
\[MD = \frac{1}{10} \times 72 = 7 . 2\]
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