English

Mean deviation for n observations x1, x2, ..., xn from their mean x¯ is given by ______.

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Question

Mean deviation for n observations x1, x2, ..., xn from their mean `barx` is given by ______.

Options

  • `sum_(i = 1)^n (x_i - barx)`

  • `1/n sum_(i = 1)^n |x_i - barx|`

  • `sum_(i = 1)^n (x_i - barx)^2`

  • `1/n sum_(i = 1)^n (x_i - barx)^2`

MCQ
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Solution

Mean deviation for n observations x1, x2, ..., xn from their mean `barx` is given by `1/n sum_(i = 1)^n |x_i - barx|`.

Explanation:

 M.D. = `1/n sum_(i = 1)^n |x_i - barx|`

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Chapter 15: Statistics - Exercise [Page 281]

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NCERT Exemplar Mathematics Exemplar [English] Class 11
Chapter 15 Statistics
Exercise | Q 25 | Page 281

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