English

The Mean Deviation of the Data 3, 10, 10, 4, 7, 10, 5 from the Mean is (A) 2 (B) 2.57 (C) 3 (D) 3.57 - Mathematics

Advertisements
Advertisements

Question

The mean deviation of the data 3, 10, 10, 4, 7, 10, 5 from the mean is

Options

  • 2    

  •  2.57       

  •  3        

  •  3.57 

MCQ
Advertisements

Solution

The given observations are 3, 10, 10, 4, 7, 10, 5.

∴ Mean,  \[x = \frac{3 + 10 + 10 + 4 + 7 + 10 + 5}{7} = \frac{49}{7} = 7\]

Now,

Mean deviation from mean, MD

\[= \frac{\sum_{} \left| x_i - 7 \right|}{7}\]

\[= \frac{\left| 3 - 7 \right| + \left| 10 - 7 \right| + \left| 10 - 7 \right| + \left| 4 - 7 \right| + \left| 7 - 7 \right| + \left| 10 - 7 \right| + \left| 5 - 7 \right|}{7}\]
\[ = \frac{4 + 3 + 3 + 3 + 0 + 3 + 2}{7}\]
\[ = \frac{18}{7}\]
\[ = 2 . 57\]

shaalaa.com
  Is there an error in this question or solution?
Chapter 32: Statistics - Exercise 32.9 [Page 51]

APPEARS IN

RD Sharma Mathematics [English] Class 11
Chapter 32 Statistics
Exercise 32.9 | Q 22 | Page 51

Video TutorialsVIEW ALL [1]

RELATED QUESTIONS

Find the mean deviation about the mean for the data.

38, 70, 48, 40, 42, 55, 63, 46, 54, 44


Find the mean deviation about the median for the data.

13, 17, 16, 14, 11, 13, 10, 16, 11, 18, 12, 17


Find the mean deviation about the mean for the data.

xi 5 10 15 20 25
fi 7 4 6 3 5

Find the mean deviation about the median for the data.

xi 5 7 9 10 12 15
fi 8 6 2 2 2 6

Find the mean deviation about the median for the data.

xi 15 21 27 30 35
fi 3 5 6 7 8

Calculate the mean deviation about the median of the observation:

3011, 2780, 3020, 2354, 3541, 4150, 5000


Calculate the mean deviation about the median of the observation:

 38, 70, 48, 34, 63, 42, 55, 44, 53, 47

 

Calculate the mean deviation from the mean for the data: 

 4, 7, 8, 9, 10, 12, 13, 17


Calculate the mean deviation from the mean for the  data:

 38, 70, 48, 40, 42, 55, 63, 46, 54, 44a


Calculate the mean deviation of the following income groups of five and seven members from their medians:

I
Income in Rs.
II
Income in Rs.
4000
4200
4400
4600
4800

 
 300
4000
4200
4400
4600
4800
5800

The lengths (in cm) of 10 rods in a shop are given below:
40.0, 52.3, 55.2, 72.9, 52.8, 79.0, 32.5, 15.2, 27.9, 30.2
 Find mean deviation from median


In 34, 66, 30, 38, 44, 50, 40, 60, 42, 51 find the number of observations lying between

\[\bar{ X } \]  − M.D. and

\[\bar{ X } \]  + M.D, where M.D. is the mean deviation from the mean.


Find the mean deviation from the mean for the data:

xi 5 7 9 10 12 15
fi 8 6 2 2 2 6

Find the mean deviation from the mean for the data:

xi 10 30 50 70 90
fi 4 24 28 16 8

Find the mean deviation from the mean for the data:

Size 20 21 22 23 24
Frequency 6 4 5 1 4

Find the mean deviation from the median for the  data:

xi 15 21 27 30 35
fi 3 5 6 7 8

 


Compute the mean deviation from the median of the following distribution:

Class 0-10 10-20 20-30 30-40 40-50
Frequency 5 10 20 5 10

The age distribution of 100 life-insurance policy holders is as follows:

Age (on nearest birth day) 17-19.5 20-25.5 26-35.5 36-40.5 41-50.5 51-55.5 56-60.5 61-70.5
No. of persons 5 16 12 26 14 12 6 5

Calculate the mean deviation from the median age


Find the mean deviation from the mean and from median of the following distribution:

Marks 0-10 10-20 20-30 30-40 40-50
No. of students 5 8 15 16 6

For a frequency distribution mean deviation from mean is computed by


The mean deviation of the series aa + da + 2d, ..., a + 2n from its mean is


The mean deviation for n observations \[x_1 , x_2 , . . . , x_n\]  from their mean \[\bar{X} \]  is given by

 
  

Let \[x_1 , x_2 , . . . , x_n\]  be n observations and  \[X\]  be their arithmetic mean. The standard deviation is given by

 

The mean deviation of the data 2, 9, 9, 3, 6, 9, 4 from the mean is ______.


Find the mean deviation about the mean of the distribution:

Size 20 21 22 23 24
Frequency 6 4 5 1 4

Find the mean deviation about the median of the following distribution:

Marks obtained 10 11 12 14 15
No. of students 2 3 8 3 4

Calculate the mean deviation about the mean of the set of first n natural numbers when n is an odd number.


Calculate the mean deviation about the mean for the following frequency distribution:

Class interval 0 – 4 4 – 8 8 – 12 12 – 16 16 – 20
Frequency 4 6 8 5 2

While calculating the mean and variance of 10 readings, a student wrongly used the reading 52 for the correct reading 25. He obtained the mean and variance as 45 and 16 respectively. Find the correct mean and the variance.


Mean deviation for n observations x1, x2, ..., xn from their mean `barx` is given by ______.


When tested, the lives (in hours) of 5 bulbs were noted as follows: 1357, 1090, 1666, 1494, 1623 
The mean deviations (in hours) from their mean is ______.


The mean of 100 observations is 50 and their standard deviation is 5. The sum of all squares of all the observations is ______.


If `barx` is the mean of n values of x, then `sum_(i = 1)^n (x_i - barx)` is always equal to ______. If a has any value other than `barx`, then `sum_(i = 1)^n (x_i - barx)^2` is ______ than `sum(x_i - a)^2`


Let X = {x ∈ N: 1 ≤ x ≤ 17} and Y = {ax + b: x ∈ X and a, b ∈ R, a > 0}. If mean and variance of elements of Y are 17 and 216 respectively then a + b is equal to ______.


If the mean deviation of number 1, 1 + d, 1 + 2d, ..., 1 + 100d from their mean is 255, then d is equal to ______.


Share
Notifications

Englishहिंदीमराठी


      Forgot password?
Use app×