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Question
A batsman scores runs in 10 innings as 38, 70, 48, 34, 42, 55, 63, 46, 54 and 44. The mean deviation about mean is
Options
8.6
6.4
10.6
7.6
None of these
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Solution
None of these
\[N = 10\]
\[X = \frac{38 + 70 + 48 + 34 + 42 + 55 + 63 + 46 + 54 + 44}{10} \]
\[ = \frac{494}{10}\]
\[ = 49 . 4\]
| xi | di = \[\left| x_i - 49 . 4 \right|\] |
| 34 | 15.4 |
| 38 | 11.4 |
| 42 | 7.4 |
| 44 | 5.4 |
| 46 | 3.4 |
| 48 | 1.4 |
| 54 | 4.6 |
| 55 | 5.6 |
| 63 | 13.6 |
| 70 | 20.6 |
|
\[\sum^n_{i =} d_i = 88 . 8\]
|
\[\text{ Mean deviation from the mean } = \frac{88 . 8}{10}\]
\[ = 8 . 88\]
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