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Calculate the Mean Deviation About the Median of the Observation:(I) 3011, 2780, 3020, 2354, 3541, 4150, 5000

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Question

Calculate the mean deviation about the median of the observation:

3011, 2780, 3020, 2354, 3541, 4150, 5000

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Solution

Formula used for mean deviation:

\[MD = \frac{1}{n} \sum^n_{i = 1} \left| d_i \right|\]

\[Here, \]

\[ d_i = x_i - M\]

 M = Median

 Arranging the data in ascending order:
2354, 2780, 3011, 3020, 3541, 4150, 5000

Here, median \[(M) = 3020\]  and n = 7. 

\[x_i\]
\[\left| d_i \right|\]
\[\left| x_i - 3020 \right|\]
3011 9
2780 240
3020 0
2354 666
3541 521
4150 1130
5000 1980
Total 4546
\[MD = \frac{1}{n} \sum^n_{i = 1} \left| d_i \right|\]

\[\Rightarrow MD = \frac{1}{7} \times 4546 = 649 . 42\] 

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Chapter 32: Statistics - Exercise 32.1 [Page 6]

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R.D. Sharma Mathematics [English] Class 11
Chapter 32 Statistics
Exercise 32.1 | Q 1.1 | Page 6

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