मराठी

Calculate the Mean Deviation About the Median of the Observation:(I) 3011, 2780, 3020, 2354, 3541, 4150, 5000

Advertisements
Advertisements

प्रश्न

Calculate the mean deviation about the median of the observation:

3011, 2780, 3020, 2354, 3541, 4150, 5000

Advertisements

उत्तर

Formula used for mean deviation:

\[MD = \frac{1}{n} \sum^n_{i = 1} \left| d_i \right|\]

\[Here, \]

\[ d_i = x_i - M\]

 M = Median

 Arranging the data in ascending order:
2354, 2780, 3011, 3020, 3541, 4150, 5000

Here, median \[(M) = 3020\]  and n = 7. 

\[x_i\]
\[\left| d_i \right|\]
\[\left| x_i - 3020 \right|\]
3011 9
2780 240
3020 0
2354 666
3541 521
4150 1130
5000 1980
Total 4546
\[MD = \frac{1}{n} \sum^n_{i = 1} \left| d_i \right|\]

\[\Rightarrow MD = \frac{1}{7} \times 4546 = 649 . 42\] 

shaalaa.com
  या प्रश्नात किंवा उत्तरात काही त्रुटी आहे का?
पाठ 32: Statistics - Exercise 32.1 [पृष्ठ ६]

APPEARS IN

आर.डी. शर्मा Mathematics [English] Class 11
पाठ 32 Statistics
Exercise 32.1 | Q 1.1 | पृष्ठ ६

व्हिडिओ ट्यूटोरियलVIEW ALL [1]

संबंधित प्रश्‍न

Find the mean deviation about the median for the data.

13, 17, 16, 14, 11, 13, 10, 16, 11, 18, 12, 17


Find the mean deviation about the mean for the data.

xi 5 10 15 20 25
fi 7 4 6 3 5

Find the mean deviation about the mean for the data.

xi 10 30 50 70 90
fi 4 24 28 16 8

Find the mean deviation about the median for the data.

xi 5 7 9 10 12 15
fi 8 6 2 2 2 6

Find the mean deviation about the mean for the data.

Height in cms Number of boys
95 - 105 9
105 - 115 13
115 - 125 26
125 - 135 30
135 - 145 12
145 - 155 10

Find the mean deviation about median for the following data:

Marks Number of girls
0-10 6
10-20 8
20-30 14
30-40 16
40-50 4
50-60 2

Calculate the mean deviation about the median of the observation:

 38, 70, 48, 34, 42, 55, 63, 46, 54, 44


Calculate the mean deviation about the median of the observation:

 34, 66, 30, 38, 44, 50, 40, 60, 42, 51


Calculate the mean deviation about the median of the observation:

 22, 24, 30, 27, 29, 31, 25, 28, 41, 42


Calculate the mean deviation about the median of the observation:

 38, 70, 48, 34, 63, 42, 55, 44, 53, 47

 

Calculate the mean deviation from the mean for the data: 

 4, 7, 8, 9, 10, 12, 13, 17


The lengths (in cm) of 10 rods in a shop are given below:
40.0, 52.3, 55.2, 72.9, 52.8, 79.0, 32.5, 15.2, 27.9, 30.2 

Find mean deviation from the mean also.

 

 


Find the mean deviation from the median for the  data:

xi 15 21 27 30 35
fi 3 5 6 7 8

 


Find the mean deviation from the median for the data: 

xi 74 89 42 54 91 94 35
fi 20 12 2 4 5 3 4

Find the mean deviation from the mean for the data:

Classes 0-100 100-200 200-300 300-400 400-500 500-600 600-700 700-800
Frequencies 4 8 9 10 7 5 4 3

 


Find the mean deviation from the mean and from median of the following distribution:

Marks 0-10 10-20 20-30 30-40 40-50
No. of students 5 8 15 16 6

Calculate mean deviation about median age for the age distribution of 100 persons given below:

Age: 16-20 21-25 26-30 31-35 36-40 41-45 46-50 51-55
Number of persons 5 6 12 14 26 12 16 9

The mean of 5 observations is 4.4 and their variance is 8.24. If three of the observations are 1, 2 and 6, find the other two observations.

 

The mean deviation of the numbers 3, 4, 5, 6, 7 from the mean is


The mean deviation for n observations \[x_1 , x_2 , . . . , x_n\]  from their mean \[\bar{X} \]  is given by

 
  

Find the mean deviation about the mean of the following data:

Size (x): 1 3 5 7 9 11 13 15
Frequency (f): 3 3 4 14 7 4 3 4

Find the mean deviation about the median of the following distribution:

Marks obtained 10 11 12 14 15
No. of students 2 3 8 3 4

Calculate the mean deviation about the mean of the set of first n natural numbers when n is an odd number.


Find the mean and variance of the frequency distribution given below:

`x` 1 ≤ x < 3 3 ≤ x < 5 5 ≤ x < 7 7 ≤ x < 10
`f` 6 4 5 1

Calculate the mean deviation about the mean for the following frequency distribution:

Class interval 0 – 4 4 – 8 8 – 12 12 – 16 16 – 20
Frequency 4 6 8 5 2

Determine mean and standard deviation of first n terms of an A.P. whose first term is a and common difference is d.


While calculating the mean and variance of 10 readings, a student wrongly used the reading 52 for the correct reading 25. He obtained the mean and variance as 45 and 16 respectively. Find the correct mean and the variance.


When tested, the lives (in hours) of 5 bulbs were noted as follows: 1357, 1090, 1666, 1494, 1623 
The mean deviations (in hours) from their mean is ______.


The mean of 100 observations is 50 and their standard deviation is 5. The sum of all squares of all the observations is ______.


If `barx` is the mean of n values of x, then `sum_(i = 1)^n (x_i - barx)` is always equal to ______. If a has any value other than `barx`, then `sum_(i = 1)^n (x_i - barx)^2` is ______ than `sum(x_i - a)^2`


Let X = {x ∈ N: 1 ≤ x ≤ 17} and Y = {ax + b: x ∈ X and a, b ∈ R, a > 0}. If mean and variance of elements of Y are 17 and 216 respectively then a + b is equal to ______.


The mean and variance of seven observations are 8 and 16, respectively. If 5 of the observations are 2, 4, 10, 12, 14, then the product of the remaining two observations is ______.


Find the mean deviation about the mean for the data.

xi 5 10 15 20 25
fi 7 4 6 3 5

Share
Notifications

Englishहिंदीमराठी


      Forgot password?
Use app×