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प्रश्न
The lengths (in cm) of 10 rods in a shop are given below:
40.0, 52.3, 55.2, 72.9, 52.8, 79.0, 32.5, 15.2, 27.9, 30.2
Find mean deviation from median
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उत्तर
Formula for the mean deviation from the median is as follows:
15.2, 27.9, 30.2, 32.5, 40, 52.3, 52.8, 55.2, 72.9, 79
| \[x_i\] |
\[\left| d_i \right| = \left| x_i - 46 . 15 \right|\]
|
| 40 | 6.15 |
| 52.3 | 6.15 |
| 55.2 | 9.05 |
| 72.9 | 26.75 |
| 52.8 | 6.65 |
| 79 | 32.85 |
| 32.5 | 13.65 |
| 15.2 | 30.95 |
| 27.9 | 18.25 |
| 30.2 | 15.95 |
| Total | 166.4 |
\[MD = \frac{1}{10} \times 166.4 = 16.64\]
Mean deviation from median in 16.64cm.
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