मराठी

Find the mean deviation about the median for the data. xi 15 21 27 30 35 fi 3 5 6 7 8 - Mathematics

Advertisements
Advertisements

प्रश्न

Find the mean deviation about the median for the data.

xi 15 21 27 30 35
fi 3 5 6 7 8
बेरीज
Advertisements

उत्तर

xi fi c.f |xi - 30| fi |xi - 30|
15 3 3 15 45
21 5 8 9 45
27 6 14 3 18
30 7 21 0 0
35 8 29 5 40
Sum 29 - - 148

Median = `(29 + 1)/2` = 15th term = 30

M.D. (M) = `(sum"f"_"i" |"x"_"i" - "M"|)/"N"`

= `148/29`

= 5.1

shaalaa.com
  या प्रश्नात किंवा उत्तरात काही त्रुटी आहे का?
पाठ 15: Statistics - Exercise 15.1 [पृष्ठ ३६०]

APPEARS IN

एनसीईआरटी Mathematics [English] Class 11
पाठ 15 Statistics
Exercise 15.1 | Q 8 | पृष्ठ ३६०

व्हिडिओ ट्यूटोरियलVIEW ALL [1]

संबंधित प्रश्‍न

Find the mean deviation about the mean for the data.

4, 7, 8, 9, 10, 12, 13, 17


Find the mean deviation about the mean for the data.

38, 70, 48, 40, 42, 55, 63, 46, 54, 44


Find the mean deviation about the mean for the data.

xi 5 10 15 20 25
fi 7 4 6 3 5

Calculate the mean deviation about median age for the age distribution of 100 persons given below:

Age Number
16 - 20 5
21 - 25 6
26 - 30 12
31 - 35 14
36 - 40 26
41 - 45 12
46 - 50 16
51 - 55 9

Calculate the mean deviation from the mean for the data: 

 4, 7, 8, 9, 10, 12, 13, 17


Calculate the mean deviation from the mean for the  data:

(iv) 36, 72, 46, 42, 60, 45, 53, 46, 51, 49

 

Calculate the mean deviation from the mean for the  data:

 38, 70, 48, 40, 42, 55, 63, 46, 54, 44a


The lengths (in cm) of 10 rods in a shop are given below:
40.0, 52.3, 55.2, 72.9, 52.8, 79.0, 32.5, 15.2, 27.9, 30.2
 Find mean deviation from median


The lengths (in cm) of 10 rods in a shop are given below:
40.0, 52.3, 55.2, 72.9, 52.8, 79.0, 32.5, 15.2, 27.9, 30.2 

Find mean deviation from the mean also.

 

 


In 34, 66, 30, 38, 44, 50, 40, 60, 42, 51 find the number of observations lying between

\[\bar{ X } \]  − M.D. and

\[\bar{ X } \]  + M.D, where M.D. is the mean deviation from the mean.


In 38, 70, 48, 34, 63, 42, 55, 44, 53, 47 find the number of observations lying between

\[\bar { X } \]  − M.D. and

\[\bar { X } \]   + M.D, where M.D. is the mean deviation from the mean.


Find the mean deviation from the mean for the data:

xi 5 10 15 20 25
fi 7 4 6 3 5

Find the mean deviation from the median for the data: 

xi 74 89 42 54 91 94 35
fi 20 12 2 4 5 3 4

Find the mean deviation from the mean for the data:

Classes 0-100 100-200 200-300 300-400 400-500 500-600 600-700 700-800
Frequencies 4 8 9 10 7 5 4 3

 


Find the mean deviation from the mean for the data:

Classes 0-10 10-20 20-30 30-40 40-50 50-60
Frequencies 6 8 14 16 4 2

Compute mean deviation from mean of the following distribution:

Mark 10-20 20-30 30-40 40-50 50-60 60-70 70-80 80-90
No. of students 8 10 15 25 20 18 9 5

The age distribution of 100 life-insurance policy holders is as follows:

Age (on nearest birth day) 17-19.5 20-25.5 26-35.5 36-40.5 41-50.5 51-55.5 56-60.5 61-70.5
No. of persons 5 16 12 26 14 12 6 5

Calculate the mean deviation from the median age


Find the mean deviation from the mean and from median of the following distribution:

Marks 0-10 10-20 20-30 30-40 40-50
No. of students 5 8 15 16 6

Calculate mean deviation from the median of the following data: 

Class interval: 0–6 6–12 12–18 18–24 24–30
Frequency 4 5 3 6 2

A batsman scores runs in 10 innings as 38, 70, 48, 34, 42, 55, 63, 46, 54 and 44. The mean deviation about mean is


The mean deviation of the numbers 3, 4, 5, 6, 7 from the mean is


The mean deviation for n observations \[x_1 , x_2 , . . . , x_n\]  from their mean \[\bar{X} \]  is given by

 
  

Find the mean deviation about the mean of the following data:

Size (x): 1 3 5 7 9 11 13 15
Frequency (f): 3 3 4 14 7 4 3 4

Find the mean deviation about the mean of the distribution:

Size 20 21 22 23 24
Frequency 6 4 5 1 4

Calculate the mean deviation about the mean of the set of first n natural numbers when n is an even number.


Calculate the mean deviation about the mean for the following frequency distribution:

Class interval 0 – 4 4 – 8 8 – 12 12 – 16 16 – 20
Frequency 4 6 8 5 2

Determine mean and standard deviation of first n terms of an A.P. whose first term is a and common difference is d.


The mean deviation of the data 3, 10, 10, 4, 7, 10, 5 from the mean is ______.


The mean of 100 observations is 50 and their standard deviation is 5. The sum of all squares of all the observations is ______.


If `barx` is the mean of n values of x, then `sum_(i = 1)^n (x_i - barx)` is always equal to ______. If a has any value other than `barx`, then `sum_(i = 1)^n (x_i - barx)^2` is ______ than `sum(x_i - a)^2`


If the mean deviation of number 1, 1 + d, 1 + 2d, ..., 1 + 100d from their mean is 255, then d is equal to ______.


Share
Notifications

Englishहिंदीमराठी


      Forgot password?
Use app×