मराठी

Calculate the Mean Deviation of the Following Income Groups of Five and Seven Members from Their Medians:Iincome in Rs.Iiincome in Rs.40004200440046004800 300400042004400460048005800

Advertisements
Advertisements

प्रश्न

Calculate the mean deviation of the following income groups of five and seven members from their medians:

I
Income in Rs.
II
Income in Rs.
4000
4200
4400
4600
4800

 
 300
4000
4200
4400
4600
4800
5800
Advertisements

उत्तर

Calculate the mean deviation for the first data set.
The data is already arranged in ascending order.
For this data set, n is equal to 5.
Also, median, 

M = 4400

\[MD = \frac{1}{n} \sum^n_{i = 1} \left| d_i \right|, \text{ where } \left| d_i \right| = \left| x_i - M \right|\]

\[x_i\]
\[\left| d_i \right| = \left| x_i - M \right|\]
4000 400
4200 200
4400 0
4600 200
4800 400
Total 1200

\[MD = \frac{1}{5} \times 1200 = 240\]

Therefore, for the income of families in the first group, the mean deviation from the median is Rs 240.
Now, consider the second data set. This is also arranged in ascending order.
Here,

n = 7.

Also, median,

M= 4400
xi
\[\left| d_i \right| = \left| x_i - M \right|\]
300 4100
4000 400
4200 200
4400 0
4600 200
4800 400
5800 1400
Total 6700

\[MD = \frac{1}{7} \times 6700 = 957 . 14\]

Therefore, for the income of families in the second group, the mean deviation from the median is Rs 957.14.

shaalaa.com
  या प्रश्नात किंवा उत्तरात काही त्रुटी आहे का?
पाठ 32: Statistics - Exercise 32.1 [पृष्ठ ६]

APPEARS IN

आर.डी. शर्मा Mathematics [English] Class 11
पाठ 32 Statistics
Exercise 32.1 | Q 3 | पृष्ठ ६

व्हिडिओ ट्यूटोरियलVIEW ALL [1]

संबंधित प्रश्‍न

Find the mean deviation about the mean for the data.

4, 7, 8, 9, 10, 12, 13, 17


Find the mean deviation about the mean for the data.

38, 70, 48, 40, 42, 55, 63, 46, 54, 44


Find the mean deviation about the median for the data.

13, 17, 16, 14, 11, 13, 10, 16, 11, 18, 12, 17


Find the mean deviation about the mean for the data.

xi 5 10 15 20 25
fi 7 4 6 3 5

Find the mean deviation about the mean for the data.

xi 10 30 50 70 90
fi 4 24 28 16 8

Calculate the mean deviation about median age for the age distribution of 100 persons given below:

Age Number
16 - 20 5
21 - 25 6
26 - 30 12
31 - 35 14
36 - 40 26
41 - 45 12
46 - 50 16
51 - 55 9

Calculate the mean deviation about the median of the observation:

 38, 70, 48, 34, 63, 42, 55, 44, 53, 47

 

Calculate the mean deviation from the mean for the data: 

 4, 7, 8, 9, 10, 12, 13, 17


Calculate the mean deviation from the mean for the  data:

 13, 17, 16, 14, 11, 13, 10, 16, 11, 18, 12, 17


Calculate the mean deviation from the mean for the  data:

 38, 70, 48, 40, 42, 55, 63, 46, 54, 44a


Find the mean deviation from the median for the data: 

xi 74 89 42 54 91 94 35
fi 20 12 2 4 5 3 4

Find the mean deviation from the mean for the data:

Classes 0-100 100-200 200-300 300-400 400-500 500-600 600-700 700-800
Frequencies 4 8 9 10 7 5 4 3

 


Compute mean deviation from mean of the following distribution:

Mark 10-20 20-30 30-40 40-50 50-60 60-70 70-80 80-90
No. of students 8 10 15 25 20 18 9 5

The age distribution of 100 life-insurance policy holders is as follows:

Age (on nearest birth day) 17-19.5 20-25.5 26-35.5 36-40.5 41-50.5 51-55.5 56-60.5 61-70.5
No. of persons 5 16 12 26 14 12 6 5

Calculate the mean deviation from the median age


Find the mean deviation from the mean and from median of the following distribution:

Marks 0-10 10-20 20-30 30-40 40-50
No. of students 5 8 15 16 6

Calculate mean deviation about median age for the age distribution of 100 persons given below:

Age: 16-20 21-25 26-30 31-35 36-40 41-45 46-50 51-55
Number of persons 5 6 12 14 26 12 16 9

Calculate mean deviation from the median of the following data: 

Class interval: 0–6 6–12 12–18 18–24 24–30
Frequency 4 5 3 6 2

For a frequency distribution mean deviation from mean is computed by


A batsman scores runs in 10 innings as 38, 70, 48, 34, 42, 55, 63, 46, 54 and 44. The mean deviation about mean is


The mean deviation of the numbers 3, 4, 5, 6, 7 from the mean is


The mean deviation of the data 3, 10, 10, 4, 7, 10, 5 from the mean is


Find the mean deviation about the mean of the following data:

Size (x): 1 3 5 7 9 11 13 15
Frequency (f): 3 3 4 14 7 4 3 4

Find the mean deviation about the median of the following distribution:

Marks obtained 10 11 12 14 15
No. of students 2 3 8 3 4

Calculate the mean deviation about the mean of the set of first n natural numbers when n is an odd number.


Calculate the mean deviation about the mean of the set of first n natural numbers when n is an even number.


Calculate the mean deviation from the median of the following data:

Class interval 0 – 6 6 – 12 12 – 18 18 – 24 24 – 30
Frequency 4 5 3 6 2

Mean deviation for n observations x1, x2, ..., xn from their mean `barx` is given by ______.


When tested, the lives (in hours) of 5 bulbs were noted as follows: 1357, 1090, 1666, 1494, 1623 
The mean deviations (in hours) from their mean is ______.


The sum of squares of the deviations of the values of the variable is ______ when taken about their arithmetic mean.


Let X = {x ∈ N: 1 ≤ x ≤ 17} and Y = {ax + b: x ∈ X and a, b ∈ R, a > 0}. If mean and variance of elements of Y are 17 and 216 respectively then a + b is equal to ______.


The mean and variance of seven observations are 8 and 16, respectively. If 5 of the observations are 2, 4, 10, 12, 14, then the product of the remaining two observations is ______.


If the mean deviation of number 1, 1 + d, 1 + 2d, ..., 1 + 100d from their mean is 255, then d is equal to ______.


Share
Notifications

Englishहिंदीमराठी


      Forgot password?
Use app×