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For a Frequency Distribution Mean Deviation from Mean is Computed by - Mathematics

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प्रश्न

For a frequency distribution mean deviation from mean is computed by

पर्याय

  • M.D. = \[\frac{\Sigma f}{\Sigma f \left| d \right|}\]

     
  • M.D. = \[\frac{\Sigma d}{\Sigma f}\]

     
  •  M.D. = \[\frac{\Sigma f d}{\Sigma f}\]

     
  • M.D. = \[\frac{\Sigma f \left| d \right|}{\Sigma f}\]

     
MCQ
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उत्तर

M.D. = \[\frac{\Sigma f \left| d \right|}{\Sigma f}\]

 
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पाठ 32: Statistics - Exercise 32.9 [पृष्ठ ५०]

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आरडी शर्मा Mathematics [English] Class 11
पाठ 32 Statistics
Exercise 32.9 | Q 1 | पृष्ठ ५०

व्हिडिओ ट्यूटोरियलVIEW ALL [1]

संबंधित प्रश्‍न

Find the mean deviation about the mean for the data.

4, 7, 8, 9, 10, 12, 13, 17


Find the mean deviation about the median for the data.

xi 15 21 27 30 35
fi 3 5 6 7 8

Find the mean deviation about the mean for the data.

Height in cms Number of boys
95 - 105 9
105 - 115 13
115 - 125 26
125 - 135 30
135 - 145 12
145 - 155 10

Calculate the mean deviation about median age for the age distribution of 100 persons given below:

Age Number
16 - 20 5
21 - 25 6
26 - 30 12
31 - 35 14
36 - 40 26
41 - 45 12
46 - 50 16
51 - 55 9

Calculate the mean deviation about the median of the observation:

 38, 70, 48, 34, 42, 55, 63, 46, 54, 44


Calculate the mean deviation about the median of the observation:

 34, 66, 30, 38, 44, 50, 40, 60, 42, 51


Calculate the mean deviation about the median of the observation:

 38, 70, 48, 34, 63, 42, 55, 44, 53, 47

 

Calculate the mean deviation from the mean for the  data:

(iv) 36, 72, 46, 42, 60, 45, 53, 46, 51, 49

 

The lengths (in cm) of 10 rods in a shop are given below:
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In 38, 70, 48, 34, 63, 42, 55, 44, 53, 47 find the number of observations lying between

\[\bar { X } \]  − M.D. and

\[\bar { X } \]   + M.D, where M.D. is the mean deviation from the mean.


Find the mean deviation from the mean for the data:

Size 1 3 5 7 9 11 13 15
Frequency 3 3 4 14 7 4 3 4

Find the mean deviation from the median for the  data:

xi 15 21 27 30 35
fi 3 5 6 7 8

 


Find the mean deviation from the mean and from median of the following distribution:

Marks 0-10 10-20 20-30 30-40 40-50
No. of students 5 8 15 16 6

Calculate mean deviation about median age for the age distribution of 100 persons given below:

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Number of persons 5 6 12 14 26 12 16 9

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The mean deviation of the numbers 3, 4, 5, 6, 7 from the mean is


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Find the mean deviation about the mean of the following data:

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Frequency (f): 3 3 4 14 7 4 3 4

Find the mean deviation about the median of the following distribution:

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Mean and standard deviation of 100 items are 50 and 4, respectively. Find the sum of all the item and the sum of the squares of the items.


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The mean deviation of the data 3, 10, 10, 4, 7, 10, 5 from the mean is ______.


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Let X = {x ∈ N: 1 ≤ x ≤ 17} and Y = {ax + b: x ∈ X and a, b ∈ R, a > 0}. If mean and variance of elements of Y are 17 and 216 respectively then a + b is equal to ______.


The mean and variance of seven observations are 8 and 16, respectively. If 5 of the observations are 2, 4, 10, 12, 14, then the product of the remaining two observations is ______.


Find the mean deviation about the mean for the data.

xi 5 10 15 20 25
fi 7 4 6 3 5

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