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प्रश्न
For a frequency distribution mean deviation from mean is computed by
विकल्प
M.D. = \[\frac{\Sigma f}{\Sigma f \left| d \right|}\]
M.D. = \[\frac{\Sigma d}{\Sigma f}\]
M.D. = \[\frac{\Sigma f d}{\Sigma f}\]
M.D. = \[\frac{\Sigma f \left| d \right|}{\Sigma f}\]
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उत्तर
M.D. = \[\frac{\Sigma f \left| d \right|}{\Sigma f}\]
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संबंधित प्रश्न
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38, 70, 48, 40, 42, 55, 63, 46, 54, 44
Find the mean deviation about the mean for the data.
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| 0-100 | 4 |
| 100-200 | 8 |
| 200-300 | 9 |
| 300-400 | 10 |
| 400-500 | 7 |
| 500-600 | 5 |
| 600-700 | 4 |
| 700-800 | 3 |
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| 95 - 105 | 9 |
| 105 - 115 | 13 |
| 115 - 125 | 26 |
| 125 - 135 | 30 |
| 135 - 145 | 12 |
| 145 - 155 | 10 |
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| 0-10 | 6 |
| 10-20 | 8 |
| 20-30 | 14 |
| 30-40 | 16 |
| 40-50 | 4 |
| 50-60 | 2 |
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| 16 - 20 | 5 |
| 21 - 25 | 6 |
| 26 - 30 | 12 |
| 31 - 35 | 14 |
| 36 - 40 | 26 |
| 41 - 45 | 12 |
| 46 - 50 | 16 |
| 51 - 55 | 9 |
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38, 70, 48, 40, 42, 55, 63, 46, 54, 44a
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\[\bar { X } \] − M.D. and
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