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The Mean Deviation for N Observations X 1 , X 2 , . . . , X N from Their Mean ¯ X is Given by

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प्रश्न

The mean deviation for n observations \[x_1 , x_2 , . . . , x_n\]  from their mean \[\bar{X} \]  is given by

 
  

विकल्प

  •  \[\sum^n_{i = 1} \left( x_i - X \right)\]

  • \[\frac{1}{n} \sum^n_{i = 1} \left( x_i - X \right)\]

     
  •   \[\sum^n_{i = 1} \left( x_i - X \right)^2\]

  •   \[\frac{1}{n} \sum^n_{i = 1} \left( x_i - X \right)^2\]

MCQ
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उत्तर

The mean deviation for n observations \[x_1 , x_2 , . . . , x_n\]  from their mean \[\bar{ X } \]  is \[\frac{1}{n} \sum^n_{i = 1} \left| x_i - X \right|\]  . 

\[\frac{1}{n} \sum^n_{i = 1} \left| x_i - X \right|\]

 
 
 
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अध्याय 32: Statistics - Exercise 32.9 [पृष्ठ ५२]

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आर.डी. शर्मा Mathematics [English] Class 11
अध्याय 32 Statistics
Exercise 32.9 | Q 23 | पृष्ठ ५२

वीडियो ट्यूटोरियलVIEW ALL [1]

संबंधित प्रश्न

Find the mean deviation about the mean for the data.

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fi 7 4 6 3 5

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xi 10 30 50 70 90
fi 4 24 28 16 8

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xi 5 7 9 10 12 15
fi 8 6 2 2 2 6

Find the mean deviation about the median for the data.

xi 15 21 27 30 35
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Find the mean deviation about the mean for the data.

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400-500 7
500-600 5
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 34, 66, 30, 38, 44, 50, 40, 60, 42, 51


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 38, 70, 48, 34, 63, 42, 55, 44, 53, 47

 

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(iv) 36, 72, 46, 42, 60, 45, 53, 46, 51, 49

 

Calculate the mean deviation from the mean for the  data:

 38, 70, 48, 40, 42, 55, 63, 46, 54, 44a


Find the mean deviation from the mean for the data:

xi 5 7 9 10 12 15
fi 8 6 2 2 2 6

Find the mean deviation from the mean for the data:

xi 10 30 50 70 90
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xi 74 89 42 54 91 94 35
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Class interval: 0–4 4–8 8–12 12–16 16–20
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