हिंदी

Find the Mean Deviation from the Mean for the Data:Classes0-100100-200200-300300-400400-500500-600600-700700-800frequencies489107543

Advertisements
Advertisements

प्रश्न

Find the mean deviation from the mean for the data:

Classes 0-100 100-200 200-300 300-400 400-500 500-600 600-700 700-800
Frequencies 4 8 9 10 7 5 4 3

 

Advertisements

उत्तर

  We will compute the mean deviation from the mean in the following way:  

Classes 
\[f_i\]
Midpoints
 

\[x_i\]
 

\[f_i x_i\]
 

\[\left| x_i - X \right|\]
=
 

\[\left| x_i - 358 \right|\]
 

\[f_i \left| x_i - X \right|\]
0−100 4 50 200 308 1232
100−200 8 150 1200 208 1664
200−300 9 250 2250 108 972
300−400 10 350 3500 8 80
400−500 7 450 3150 92 644
500−600 5 550 2750 192 960
600−700 4 650 2600 292 1168
700−800 3 750 2250 392 1176
 
 

\[\sum^8_{i = 1} f_i = 50\]
 
 

\[\sum^8_{i = 1} f_ix_i= 17900\]
  \[\sum^8_{i = 1} f_i \left| x_i - X \right| = 7896\]

 

 

\[N = \sum^6_{i = 1} f_i = 50\] and 

\[\sum^6_{i = 1} f_i x_i = 17900\]

\[\bar{ X }  = \frac{\sum^{8} _{i = 1} f_i x_i}{\sum ^8_{i = 1} f_i} = \frac{17900}{50} = 358\]

\[\therefore \text{ Mean deviation } = \frac{1}{N} \sum^8_{i = 1} f_i \left| x_i - X \right|\]
\[ = \frac{7896}{50}\]
\[ = 157 . 92\]

shaalaa.com
  क्या इस प्रश्न या उत्तर में कोई त्रुटि है?
अध्याय 32: Statistics - Exercise 32.3 [पृष्ठ १६]

APPEARS IN

आर.डी. शर्मा Mathematics [English] Class 11
अध्याय 32 Statistics
Exercise 32.3 | Q 2.1 | पृष्ठ १६

वीडियो ट्यूटोरियलVIEW ALL [1]

संबंधित प्रश्न

Find the mean deviation about the mean for the data.

4, 7, 8, 9, 10, 12, 13, 17


Find the mean deviation about the mean for the data.

38, 70, 48, 40, 42, 55, 63, 46, 54, 44


Find the mean deviation about the median for the data.

13, 17, 16, 14, 11, 13, 10, 16, 11, 18, 12, 17


Find the mean deviation about the median for the data.

xi 15 21 27 30 35
fi 3 5 6 7 8

Find the mean deviation about the mean for the data.

Height in cms Number of boys
95 - 105 9
105 - 115 13
115 - 125 26
125 - 135 30
135 - 145 12
145 - 155 10

Find the mean deviation about median for the following data:

Marks Number of girls
0-10 6
10-20 8
20-30 14
30-40 16
40-50 4
50-60 2

Calculate the mean deviation about the median of the observation:

 38, 70, 48, 34, 42, 55, 63, 46, 54, 44


Calculate the mean deviation from the mean for the data: 

 4, 7, 8, 9, 10, 12, 13, 17


Calculate the mean deviation from the mean for the  data:

 13, 17, 16, 14, 11, 13, 10, 16, 11, 18, 12, 17


In 34, 66, 30, 38, 44, 50, 40, 60, 42, 51 find the number of observations lying between

\[\bar{ X } \]  − M.D. and

\[\bar{ X } \]  + M.D, where M.D. is the mean deviation from the mean.


In 38, 70, 48, 34, 63, 42, 55, 44, 53, 47 find the number of observations lying between

\[\bar { X } \]  − M.D. and

\[\bar { X } \]   + M.D, where M.D. is the mean deviation from the mean.


Find the mean deviation from the mean for the data:

xi 5 10 15 20 25
fi 7 4 6 3 5

Find the mean deviation from the mean for the data:

xi 10 30 50 70 90
fi 4 24 28 16 8

Find the mean deviation from the median for the  data:

xi 15 21 27 30 35
fi 3 5 6 7 8

 


Find the mean deviation from the median for the data: 

xi 74 89 42 54 91 94 35
fi 20 12 2 4 5 3 4

Compute mean deviation from mean of the following distribution:

Mark 10-20 20-30 30-40 40-50 50-60 60-70 70-80 80-90
No. of students 8 10 15 25 20 18 9 5

Calculate mean deviation about median age for the age distribution of 100 persons given below:

Age: 16-20 21-25 26-30 31-35 36-40 41-45 46-50 51-55
Number of persons 5 6 12 14 26 12 16 9

Calculate the mean deviation about the mean for the following frequency distribution:
 

Class interval: 0–4 4–8 8–12 12–16 16–20
Frequency 4 6 8 5 2

Calculate mean deviation from the median of the following data: 

Class interval: 0–6 6–12 12–18 18–24 24–30
Frequency 4 5 3 6 2

The mean deviation of the series aa + da + 2d, ..., a + 2n from its mean is


A batsman scores runs in 10 innings as 38, 70, 48, 34, 42, 55, 63, 46, 54 and 44. The mean deviation about mean is


The mean deviation of the numbers 3, 4, 5, 6, 7 from the mean is


The mean deviation for n observations \[x_1 , x_2 , . . . , x_n\]  from their mean \[\bar{X} \]  is given by

 
  

Let \[x_1 , x_2 , . . . , x_n\]  be n observations and  \[X\]  be their arithmetic mean. The standard deviation is given by

 

Find the mean deviation about the mean of the distribution:

Size 20 21 22 23 24
Frequency 6 4 5 1 4

Find the mean deviation about the median of the following distribution:

Marks obtained 10 11 12 14 15
No. of students 2 3 8 3 4

Calculate the mean deviation about the mean of the set of first n natural numbers when n is an odd number.


Mean and standard deviation of 100 items are 50 and 4, respectively. Find the sum of all the item and the sum of the squares of the items.


Find the mean and variance of the frequency distribution given below:

`x` 1 ≤ x < 3 3 ≤ x < 5 5 ≤ x < 7 7 ≤ x < 10
`f` 6 4 5 1

Determine mean and standard deviation of first n terms of an A.P. whose first term is a and common difference is d.


When tested, the lives (in hours) of 5 bulbs were noted as follows: 1357, 1090, 1666, 1494, 1623 
The mean deviations (in hours) from their mean is ______.


If `barx` is the mean of n values of x, then `sum_(i = 1)^n (x_i - barx)` is always equal to ______. If a has any value other than `barx`, then `sum_(i = 1)^n (x_i - barx)^2` is ______ than `sum(x_i - a)^2`


The mean and variance of seven observations are 8 and 16, respectively. If 5 of the observations are 2, 4, 10, 12, 14, then the product of the remaining two observations is ______.


Find the mean deviation about the mean for the data.

xi 5 10 15 20 25
fi 7 4 6 3 5

Share
Notifications

Englishहिंदीमराठी


      Forgot password?
Use app×