हिंदी

Find the Mean Deviation from the Mean for the Data:Classes95-105105-115115-125125-135135-145145-155frequencies91316263012 - Mathematics

Advertisements
Advertisements

प्रश्न

Find the mean deviation from the mean for the data:

Classes 95-105 105-115 115-125 125-135 135-145 145-155
Frequencies 9 13 16 26 30 12

 

Advertisements

उत्तर

We will compute the mean deviation from the mean in the following way: 

Classes  Frequency 
\[f_i\]
Midpoints
\[x_i\]
 

\[f_i x_i\]
 

\[\left| x_i - X \right|\]
=
\[\left| x_i - 128 . 58 \right|\]
\[f_i \left| x_i - X \right|\]
95−105 9 100 900 28.58 257.22
105−115 13 110 1430 18.58 241.54
115−125 16 120 1920 8.58 137.28
125−135 26 130 3380 1.42 36.92
135−145 30 140 4200 11.42 342.6
145−155 12 150 1800 21.42 257.04
 
 

\[\sum^6_{i = 1} f_i = 106\]
 
 

\[\sum^6_{i = 1} f_i x_i = 13630\]
  \[\sum^8_{i = 1}|  f_i x_i  |- \bar{x}= 1272.6\]

 

\[N = \sum^6_{i = 1} f_i = 106\] and

\[\sum^6_{i = 1} f_i x_i = 13630\]

\[\therefore X = \frac{\sum^6_{i = 1} f_i x_i}{\sum^6_{i = 1} f_i}\]

\[ = \frac{13630}{106}\]

\[ = 128 . 58\]

\[\therefore \text{ Mean deviation } = \frac{1}{N} \sum^8_{i = 1} f_i \left| x_i - X \right|\]

\[ = \frac{1272 . 6}{106}\]

\[ = 12 . 005\]

shaalaa.com
  क्या इस प्रश्न या उत्तर में कोई त्रुटि है?
अध्याय 32: Statistics - Exercise 32.3 [पृष्ठ १६]

APPEARS IN

आरडी शर्मा Mathematics [English] Class 11
अध्याय 32 Statistics
Exercise 32.3 | Q 2.2 | पृष्ठ १६

वीडियो ट्यूटोरियलVIEW ALL [1]

संबंधित प्रश्न

Find the mean deviation about the mean for the data.

4, 7, 8, 9, 10, 12, 13, 17


Find the mean deviation about the mean for the data.

38, 70, 48, 40, 42, 55, 63, 46, 54, 44


Find the mean deviation about the median for the data.

xi 5 7 9 10 12 15
fi 8 6 2 2 2 6

Find the mean deviation about the mean for the data.

Income per day in ₹ Number of persons
0-100 4
100-200 8
200-300 9
300-400 10
400-500 7
500-600 5
600-700 4
700-800 3

Find the mean deviation about median for the following data:

Marks Number of girls
0-10 6
10-20 8
20-30 14
30-40 16
40-50 4
50-60 2

Calculate the mean deviation about the median of the observation:

3011, 2780, 3020, 2354, 3541, 4150, 5000


Calculate the mean deviation about the median of the observation:

 38, 70, 48, 34, 42, 55, 63, 46, 54, 44


Calculate the mean deviation about the median of the observation:

 34, 66, 30, 38, 44, 50, 40, 60, 42, 51


Calculate the mean deviation about the median of the observation:

 22, 24, 30, 27, 29, 31, 25, 28, 41, 42


Calculate the mean deviation from the mean for the  data:

(iv) 36, 72, 46, 42, 60, 45, 53, 46, 51, 49

 

Calculate the mean deviation from the mean for the  data:

 38, 70, 48, 40, 42, 55, 63, 46, 54, 44a


Calculate the mean deviation of the following income groups of five and seven members from their medians:

I
Income in Rs.
II
Income in Rs.
4000
4200
4400
4600
4800

 
 300
4000
4200
4400
4600
4800
5800

The lengths (in cm) of 10 rods in a shop are given below:
40.0, 52.3, 55.2, 72.9, 52.8, 79.0, 32.5, 15.2, 27.9, 30.2
 Find mean deviation from median


In 34, 66, 30, 38, 44, 50, 40, 60, 42, 51 find the number of observations lying between

\[\bar{ X } \]  − M.D. and

\[\bar{ X } \]  + M.D, where M.D. is the mean deviation from the mean.


Find the mean deviation from the mean for the data:

Size 20 21 22 23 24
Frequency 6 4 5 1 4

Find the mean deviation from the median for the data: 

xi 74 89 42 54 91 94 35
fi 20 12 2 4 5 3 4

Compute the mean deviation from the median of the following distribution:

Class 0-10 10-20 20-30 30-40 40-50
Frequency 5 10 20 5 10

The age distribution of 100 life-insurance policy holders is as follows:

Age (on nearest birth day) 17-19.5 20-25.5 26-35.5 36-40.5 41-50.5 51-55.5 56-60.5 61-70.5
No. of persons 5 16 12 26 14 12 6 5

Calculate the mean deviation from the median age


Find the mean deviation from the mean and from median of the following distribution:

Marks 0-10 10-20 20-30 30-40 40-50
No. of students 5 8 15 16 6

The mean of 5 observations is 4.4 and their variance is 8.24. If three of the observations are 1, 2 and 6, find the other two observations.

 

The mean deviation from the median is


The mean deviation of the data 3, 10, 10, 4, 7, 10, 5 from the mean is


The mean deviation of the data 2, 9, 9, 3, 6, 9, 4 from the mean is ______.


Calculate the mean deviation about the mean of the set of first n natural numbers when n is an even number.


Calculate the mean deviation about the mean for the following frequency distribution:

Class interval 0 – 4 4 – 8 8 – 12 12 – 16 16 – 20
Frequency 4 6 8 5 2

Calculate the mean deviation from the median of the following data:

Class interval 0 – 6 6 – 12 12 – 18 18 – 24 24 – 30
Frequency 4 5 3 6 2

When tested, the lives (in hours) of 5 bulbs were noted as follows: 1357, 1090, 1666, 1494, 1623 
The mean deviations (in hours) from their mean is ______.


The mean of 100 observations is 50 and their standard deviation is 5. The sum of all squares of all the observations is ______.


If `barx` is the mean of n values of x, then `sum_(i = 1)^n (x_i - barx)` is always equal to ______. If a has any value other than `barx`, then `sum_(i = 1)^n (x_i - barx)^2` is ______ than `sum(x_i - a)^2`


Let X = {x ∈ N: 1 ≤ x ≤ 17} and Y = {ax + b: x ∈ X and a, b ∈ R, a > 0}. If mean and variance of elements of Y are 17 and 216 respectively then a + b is equal to ______.


The mean and variance of seven observations are 8 and 16, respectively. If 5 of the observations are 2, 4, 10, 12, 14, then the product of the remaining two observations is ______.


If the mean deviation of number 1, 1 + d, 1 + 2d, ..., 1 + 100d from their mean is 255, then d is equal to ______.


Share
Notifications

Englishहिंदीमराठी


      Forgot password?
Use app×