हिंदी

The mean of 100 observations is 50 and their standard deviation is 5. The sum of all squares of all the observations is ______.

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प्रश्न

The mean of 100 observations is 50 and their standard deviation is 5. The sum of all squares of all the observations is ______.

विकल्प

  • 50000

  • 250000

  • 252500

  • 255000

MCQ
रिक्त स्थान भरें
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उत्तर

The mean of 100 observations is 50 and their standard deviation is 5. The sum of all squares of all the observations is 252500.

Explanation:

Here `barx = (sumx_i)/n`

50 = `(sumx_i)/100`

⇒ `sumx_i` = 5000

∴ S.D. = `sqrt((sumx_i^2)/n - ((sumx_i^2)/n)^2`

5 = `sqrt((sumx_i^2)/100 - (5000/100)^2`

⇒ 25 = `(sumx_i^2)/100 - 2500`

⇒ `(sumx_i^2)/100 = 2500 + 25`

⇒ `(sumx_i^2)/00` = 2525

∴ `sumx_i^2 = 255 xx 100` = 252500

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अध्याय 15: Statistics - Exercise [पृष्ठ २८२]

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एनसीईआरटी एक्झांप्लर Mathematics Exemplar [English] Class 11
अध्याय 15 Statistics
Exercise | Q 30 | पृष्ठ २८२

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