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Find the Mean, Variance and Standard Deviation for the Data: 2, 4, 5, 6, 8, 17. - Mathematics

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Question

Find the mean, variance and standard deviation for the data:

 2, 4, 5, 6, 8, 17.

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Solution

2,4,5,6,8,17

\[\text{ Mean } = \bar{ X } = \frac{2 + 4 + 5 + 6 + 8 + 17}{6} = \frac{42}{6} = 7\]

\[x_i\]
\[\left( x_i - X \right) = \left( x_i - 7 \right)\]
\[\left( x_i - 7 \right)^2\]
2 -5 25
4 -3 9
5 -2 4
6 -1 1
8 1 1
17 10 100
   
\[\sum^6_{i = 1} \left( x_i - X \right)^2 = 140\]

 

n =6

\[\text{ Variance } (X) = \frac{\sum^6_{i = 1} \left( x_i - X \right)^2}{n}\]

\[ = \frac{140}{6}\]

\[ = 23 . 33\]

\[\text{ Standard deviation } = \sqrt{\text{ Variance }(X}) \]

\[ = \sqrt{23 . 33}\]

\[ = 4 . 83\]

 

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Chapter 32: Statistics - Exercise 32.4 [Page 28]

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RD Sharma Mathematics [English] Class 11
Chapter 32 Statistics
Exercise 32.4 | Q 1.1 | Page 28

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