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Find the mean and variance for the first 10 multiples of 3. - Mathematics

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Question

Find the mean and variance for the first 10 multiples of 3.

Sum
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Solution

First 10 multiples of 3: 3, 6, 9, 12, 15, 18, 21, 24, 27, 30

xi yi = `(x_i - 15)/3` `y_i^2`
3 −4 16
6 −3 9
9 −2 4
12 −1 1
15 0 0
18 1 1
21 2 4
24 3 9
27 4 16
30 5 25
Sum 5 85

Mean `overline x = "A" + (sumy_i)/n xx h`

= `15 + 5/10 xx 3`

= 15 + 1.5 

= 16.5

Variance, `σ^2 = h^2/h^2 [n sum y_i^2 - (sum y_i)^2]`

= `9/100 [10 xx 85 - 25]`

= `9/100 [850 - 25]`

= `(9 xx 825)/100`

= `7425/100`

= 74.25

Hence, mean = 16.5, variance = 74.25

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Chapter 15: Statistics - Exercise 15.2 [Page 371]

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NCERT Mathematics [English] Class 11
Chapter 15 Statistics
Exercise 15.2 | Q 3 | Page 371

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