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Question
At sea level, the atmospheric pressure is 1.04 x 105 Pa. Assuming g = 10 m s-2 and density of air to be uniform and equal to 1.3 kg m-3, find the height of the atmosphere.
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Solution
Atmospheric pressure , P = 1.04 × 105 Pa
Acceleration due to gravity , g = 10 ms-2
Density , ρ = 1.3 kgm-3
Let h be the height of the atmosphere.
P = hρg
∴ h = `P/(ρg)` = `(1.04 xx 10^5)/(1.3 xx 10)` = 8000 m
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