Advertisements
Advertisements
Question
At sea level, the atmospheric pressure is 1.04 x 105 Pa. Assuming g = 10 m s-2 and density of air to be uniform and equal to 1.3 kg m-3, find the height of the atmosphere.
Advertisements
Solution
Atmospheric pressure , P = 1.04 × 105 Pa
Acceleration due to gravity , g = 10 ms-2
Density , ρ = 1.3 kgm-3
Let h be the height of the atmosphere.
P = hρg
∴ h = `P/(ρg)` = `(1.04 xx 10^5)/(1.3 xx 10)` = 8000 m
APPEARS IN
RELATED QUESTIONS
You want to buy a house. Would you like to buy a house having windows but no ventilators? Explain your answer.
The atmospheric pressure is nearly 105 Pa.
How will you show that there is vacuum above the surface of mercury in a barometer? What name is given to this vacuum?
Mention two demerits of a simple barometer and state how they are removed in a Fortin barometer .
Explain briefly the factors that affect Atmospheric Pressure.
State briefly, how and why the atmospheric pressure of a place varies with the altitude. Draw an approximate graph to illustrate this variation.
What is the purpose of a barometer? State two major defects of a simple barometer.
A solid weighs 2.10 N in air. It has a relative density of 8.4. How much will the body weigh if placed: In a liquid of relative density 1.2
Figure shows a child blowing air with a straw near the opening of another straw which has its other end in a soft drink bottle. It was observed that the level of the soft drink in the straw rises up as soon as air is blown over its open end. Which one of the following best explains the reason for rise in level of the drink?
