Advertisements
Advertisements
Question
A solid weighs 2.10 N in air. It has a relative density of 8.4. How much will the body weigh if placed: In a liquid of relative density 1.2
Advertisements
Solution
Relative density of liquid =1.2
We know
Relative density of liquid = Loss of weight of solid in liquid/loss of weight of solid in water.
Loss of weight of solid in liquid = Relative density X loss of weight of solid in water.
Loss of weight of solid in liquid = 1.2 X 0.25 = 0.3 N.
Weight of solid in liquid = weight of solid in the air - loss of weight of solid in a liquid.
Weight of solid in liquid = 2.10 - 0.3 = 1.8 N.
APPEARS IN
RELATED QUESTIONS
Write the numerical value of the atmospheric pressure on the surface of earth in pascal.
How is the barometric height of a simple barometer affected if Its tube is pushed down into the trough of mercury?
How is the barometric height of a simple barometer affected if Its tube is slightly tilted from vertical?
Draw a simple labelled diagram of a Fortin barometer and state how it is used to measure the atmospheric pressure.
Give reasons for the following:
As we go higher, the atmospheric pressure decreases.
What is meant by atmospheric pressure?
What is an aneroid barometer?
Draw a neat and labeled diagram to explain its construction and working.
Air pressure is expressed in ______.
The value of the atmospheric pressure at sea level is
