Advertisements
Advertisements
Question
A solid weighs 2.10 N in air. It has a relative density of 8.4. How much will the body weigh if placed: In a liquid of relative density 1.2
Advertisements
Solution
Relative density of liquid =1.2
We know
Relative density of liquid = Loss of weight of solid in liquid/loss of weight of solid in water.
Loss of weight of solid in liquid = Relative density X loss of weight of solid in water.
Loss of weight of solid in liquid = 1.2 X 0.25 = 0.3 N.
Weight of solid in liquid = weight of solid in the air - loss of weight of solid in a liquid.
Weight of solid in liquid = 2.10 - 0.3 = 1.8 N.
APPEARS IN
RELATED QUESTIONS
Nose bleeding may occur at a high altitude because
Give two reasons for use of mercury as a barometric liquid.
State two advantages of an aneroid barometer over a simple barometer.
At a given place, a mercury barometer records a pressure of 0.70 m of Hg. What would be the height of water column if mercury in barometer is replaced by water? Take density of mercury to be = 13.6 × 103 kg m-3.
Select the correct option.
As we move upwards, the atmospheric pressure
If there is low pressure at the equator, what will be the condition of air pressure in the Arctic Zone?
Air pressure is expressed in ______.
What is meant by atmospheric pressure?
What does low pressure and high pressure lead to?
Why do Scuba divers wear special suits and equipment?
