Advertisements
Advertisements
प्रश्न
A solid weighs 2.10 N in air. It has a relative density of 8.4. How much will the body weigh if placed: In a liquid of relative density 1.2
Advertisements
उत्तर
Relative density of liquid =1.2
We know
Relative density of liquid = Loss of weight of solid in liquid/loss of weight of solid in water.
Loss of weight of solid in liquid = Relative density X loss of weight of solid in water.
Loss of weight of solid in liquid = 1.2 X 0.25 = 0.3 N.
Weight of solid in liquid = weight of solid in the air - loss of weight of solid in a liquid.
Weight of solid in liquid = 2.10 - 0.3 = 1.8 N.
APPEARS IN
संबंधित प्रश्न
What do you mean by atmospheric pressure?
Give reason for the following:
A balloon collapses when air is removed from it.
How will you show that there is vacuum above the surface of mercury in a barometer? What name is given to this vacuum?
Mention two demerits of a simple barometer and state how they are removed in a Fortin barometer .
What do the following indicate in a barometer regarding weather : sudden fall in the mercury level
What do the following indicate in a barometer regarding weather : Gradual rise in the mercury level?
At sea level, the atmospheric pressure is 1.04 x 105 Pa. Assuming g = 10 m s-2 and density of air to be uniform and equal to 1.3 kg m-3, find the height of the atmosphere.
Air pressure is expressed in ______.
The standard air pressure at sea level is ______.
Give Reason for the following
Our ears pop in Airplanes.
