Question

At sea level, the atmospheric pressure is 1.04 x 10⁵ Pa. Assuming g = 10 m s^-2 and density of air to be uniform and equal to 1.3 kg m^-3, find the height of the atmosphere.

Answer 1

Atmospheric pressure , P = 1.04 × 10⁵ Pa

Acceleration due to gravity , g = 10 ms^-2

Density , ρ = 1.3 kgm^-3

Let h be the height of the atmosphere.

P = hρg

∴ h = `P/(ρg)` = `(1.04 xx 10^5)/(1.3 xx 10)` = 8000 m