Advertisements
Advertisements
Question
Assuming the density of air to be 1.295 kg m-3, find the fall in barometric height in mm of Hg at a height of 107 m above the sea level. Take density of mercury = 13.6 × 103 kg m-3.
Advertisements
Solution
Let h = 107 m be the height above sea level
∴ `P_h - P_(sea) = ρ_(air) gh`
∴ `ρ_m gh_f - ρ_m gh_i = ρ_(air) gh`
∴ `ρ_m gΔh = ρ_(air)gh`
∴ `Δh = (ρ_(air) h)/ρ_m = (1.295 xx 107)/(13.6 xx 10^3)`
∴ Δh = 0.010 m of Hg
∴ Δh = 10 mm of Hg
APPEARS IN
RELATED QUESTIONS
Complete the following sentence :
An empty tin container with its mouth closed has an average density equal to that of a liquid. The container is taken 2 m below the surface of that liquid and is left there. Then the container will ____________ .
Express the relationship between the C.G.S. and S.I. units of density.
'The density of iron is 7800 kg m-3'. What do you understand by this statement?
The density of water is :
A piece of iron weighs 44.5 gf in air. If the density of iron is 8.9 × 103, find the weight of iron piece when immersed in water.
Explain why an iron nail floats on mercury, but it sinks in water.
Hint : Density of iron is less than that of mercury, but more than that of water.
A block of wood of mass 24 kg floats on water. The volume of wood is 0.032 m3. Find:
- the volume of block below the surface of water,
- the density of wood.
(Density of water = 1000 kg m−3)
A wooden cube of side 10 cm has mass 700 g. What part of it remains above the water surface while floating vertically on water surface?
A body of mass 50 g is floting in water. What is the apparent weight of body in water? Explain your answer.
A body of mass ‘m’ is floating in a liquid of density ‘p’
what is the loss of weight of body?
