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Question
A piece of iron weighs 44.5 gf in air. If the density of iron is 8.9 × 103, find the weight of iron piece when immersed in water.
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Solution
Density of iron = 8.9 × 103 = 8900
Density of water = 1000
Weight of iron when immersed in water is given by
Weight of iron in water = Weight of iron in air × `(1 - "density of water"/"density of iron")`
= `44.5 "gf" xx (1 - 1000/8900)`
= 39.5 kgf
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