Advertisements
Advertisements
Question
Advertisements
Solution
Edge of metal cube = 5 cm.
Density of the metal cube = 9 gcm-3 = 9 × 103 kgm-3.
Volume of the metal cube = 125 cm3 = 125 × 10-6 m3.
Mass of the metal cube =9 × 103 ×125 × 10-6 = 1125 × 10-3 =1.125 kg.
Weight of the liquid = mass × gravity = 1.125 × 10 = 11.25 N.
Density of liquid = 1.2 gcm-3= 1.2 × 103 kgm-3.
Upthrust of the liquid = V × p × g.
Upthrust = 125 × 10-6 × 1.2 × 103 × 10 = 1.5 N.
The apparent weight of the body = weight of liquid - upthrust
Apparent weight = 11.25 N - 1.5 N = 9.75 N
Tension in the string is equal to the apparent weight of the body
So, the tension in the string would be 9.75 N.
APPEARS IN
RELATED QUESTIONS
A body held completely immersed inside a liquid experiences two forces:
(i) F1, the force due to gravity and
(ii) F2, the buoyant force.
Draw a diagram showing the direction of these forces acting on the body and state the condition when the body will float or sink.
A piece of iron weighs 44.5 gf in air. If the density of iron is 8.9 × 103, find the weight of iron piece when immersed in water.
How does the density ρs of a substance determine whether a solid piece of that substance will float or sink in a given liquid ρL?
Explain the following :
A balloon filled with hydrogen rises to a certain height and then stops rising further.
A solid lighter than water is found to weigh 7.5 gf in air. When tied to a sinker the combination is found to weigh .If the sinker alone weighs 72.5 gf in water, find R.D. of solid.
An inflated balloon is placed inside a big glass jar which is connected to an evacuating pump. What will you observe when the evacuating pump starts working? Give a reason for your answer.
Select the correct option:
When a body is floating in a liquid:
A body weighs 300 gf in air and 280 gf when completely immersed in water. Calculate:
(i) The loss in weight of the body,
(ii) The upthrust on the body.
Complete the following result:
Mass = _______ × density
