Advertisements
Advertisements
Question
A body weighs 300 gf in air and 280 gf when completely immersed in water. Calculate:
(i) The loss in weight of the body,
(ii) The upthrust on the body.
Advertisements
Solution
Weight of the body in air = 300 gf.
Apparent Weight of the completely immersed body in water = 280 gf.
(i) Loss in weight of the body = Weight of body in air - apparent weight of the immersed body.
Loss in weight = 300 gf - -280 gf = 20 gf.
(ii) As upthrust on the body = loss in weight
(iii) So uptrust = 20 gf.
APPEARS IN
RELATED QUESTIONS
A body of density ρ sinks in a liquid of density ρL. The densities ρ and ρL are related as :
Define the term density.
Calculate the mass of air in a room of dimensions 4.5 m × 3.5 m × 2.5 m if the density of air at N.T.P. is 1.3 kgm-3 .
What can you say about the average density of a ship floating on water in relation to the density of water?
A block of wood of mass 24 kg floats on water. The volume of wood is 0.032 m3. Find:
- the volume of block below the surface of water,
- the density of wood.
(Density of water = 1000 kg m−3)
A wooden cube of side 10 cm has mass 700 g. What part of it remains above the water surface while floating vertically on water surface?
If the density of ice is 0.9 g cm-3, then what portion of an iceberg will remain below the surface of water in sea? (Density of sea water = 1.1 g cm-3)
Write the SI units of Density
Write the SI units of Relative density
