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Question
If the density of ice is 0.9 g cm-3, then what portion of an iceberg will remain below the surface of water in sea? (Density of sea water = 1.1 g cm-3)
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Solution
Density of ice (ρ1)= 0.9 gcm-3
Density of sea water (ρs) = 1.1 gcm-3
Let the total volume of the iceberg be V and the volume of immersed portion be v.
According to the law of floatation,
`"v"/"V" = ρ_1/ρ_s`
or , `"v"/"V" = 0.9/1.1 = 9/11`
or , v = `9/11`V
Thus , ice floats with `9/11`th part of its volume above the surface sea water.
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