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A metal cube of 5 cm edge and density 9 g cm-3 is suspended by a thread so as to be completely immersed in a liquid of density 1.2 g cm-3. Find the tension in the thread. (Take g = 10 ms-2).

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प्रश्न

A metal cube of 5 cm edge and density 9 g cm-3 is suspended by a thread so as to be completely immersed in a liquid of density 1.2 g cm-3. Find the tension in the thread. (Take g = 10 ms-2).
संक्षेप में उत्तर
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उत्तर

Edge of metal cube = 5 cm.
Density of the metal cube = 9 gcm-3 = 9 × 103 kgm-3.
Volume of the metal cube = 125 cm3 = 125 × 10-6 m3.
Mass of the metal cube =9 × 103 ×125 × 10-6 = 1125 × 10-3 =1.125 kg.
Weight of the liquid = mass × gravity = 1.125 × 10 = 11.25 N.
Density of liquid = 1.2 gcm-3= 1.2 × 103 kgm-3.
Upthrust of the liquid = V × p × g.
Upthrust = 125 × 10-6 × 1.2 × 103 × 10 = 1.5 N.
The apparent weight of the body = weight of liquid - upthrust
Apparent weight = 11.25 N - 1.5 N = 9.75 N
Tension in the string is equal to the apparent weight of the body
So, the tension in the string would be 9.75 N.

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Relation Between Volume of Submerged Part of a Floating Body, the Densities of Liquid and the Body
  क्या इस प्रश्न या उत्तर में कोई त्रुटि है?
अध्याय 4: Fluids - Exercise 2 [पृष्ठ १७३]

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फ्रैंक Physics [English] Class 9 ICSE
अध्याय 4 Fluids
Exercise 2 | Q 11 | पृष्ठ १७३

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