Advertisements
Advertisements
प्रश्न
A body of volume 100 cm3 weighs 5 kgf in air. It is completely immersed in a liquid of density 1.8 × 103 kg m-3. Find:
- The upthrust due to liquid and
- The weight of the body in liquid.
Advertisements
उत्तर
Volume of body = V = 100 cm3
= 100 × 10-6
= 10-4m3
Weight in air W = 5 kgf
Density of liquid d = 1.8 × 103 kg/m3
(i) Upthrust due to liquid = Volume of the solid submerged × density 0
= 10-4 × 1.8 × 103 × g
= 0.18 gN
= 0.18 kgf
(ii) Weight of body in liquid = Weight of body in air - upthrust
= 5 kgf - 0.18 kgf
= 4.82 kgf
APPEARS IN
संबंधित प्रश्न
Define the term density.
What are the units density in (i) C.G.S. and (ii) S.I. system .
Water is heated from 0°C to 10°C . How does the density of water change with temperature?
A loaded cargo ship sails from sea water to river water. State and Explain your observations.
Explain the following :
An egg sinks in fresh water, but floats in a strong salt solution.
A piece of wax floats on brine. What fraction of its volume is immersed?
Density of wax = 0.95 g cm-3, Density of brine = 1.1 g cm-3.
If the density of ice is 0.9 g cm-3, then what portion of an iceberg will remain below the surface of water in sea? (Density of sea water = 1.1 g cm-3)
An inflated balloon is placed inside a big glass jar which is connected to an evacuating pump. What will you observe when the evacuating pump starts working? Give a reason for your answer.
Write the SI units of Density
A wooden cube of side 10 cm has a mass of 700 g. It will float in the water with:
(a) Half of its volume inside the water
(b) 3 cm height above the water surface
(c) 7 cm height above the water surface
(d) Just inside the water surface.
