Advertisements
Advertisements
प्रश्न
A body of volume 100 cm3 weighs 5 kgf in air. It is completely immersed in a liquid of density 1.8 × 103 kg m-3. Find:
- The upthrust due to liquid and
- The weight of the body in liquid.
Advertisements
उत्तर
Volume of body = V = 100 cm3
= 100 × 10-6
= 10-4m3
Weight in air W = 5 kgf
Density of liquid d = 1.8 × 103 kg/m3
(i) Upthrust due to liquid = Volume of the solid submerged × density 0
= 10-4 × 1.8 × 103 × g
= 0.18 gN
= 0.18 kgf
(ii) Weight of body in liquid = Weight of body in air - upthrust
= 5 kgf - 0.18 kgf
= 4.82 kgf
APPEARS IN
संबंधित प्रश्न
Define the term density.
Express the relationship between the C.G.S. and S.I. units of density.
A body weighs W gf in air and W1 gf when it is completely immersed in water. Find: (i) Volume of the body, (ii) Upthrust on the body and (iii) Relative density of the material of the body.
The density of water is :
A man first swims in sea water and then in river water. (i) Compare the weights of sea water and river water displaced by him.
(ii) Where does he find it easier to swim and why?
Explain the following :
Toy balloons filled with hydrogen rise to the ceiling, but if they are filled with carbon dioxide, then they sink to the floor.
Explain the following :
A balloon filled with hydrogen rises to a certain height and then stops rising further.
Select the correct option:
With the increase in the density of the fluid, the upthrust experienced by a body immersed in it:
Select the correct option:
A body has density 9.6 gcm -3. Its density in SI system is:
Complete the following result:
Mass = _______ × density
