Advertisements
Advertisements
प्रश्न
A body of volume 100 cm3 weighs 5 kgf in air. It is completely immersed in a liquid of density 1.8 × 103 kg m-3. Find:
- The upthrust due to liquid and
- The weight of the body in liquid.
Advertisements
उत्तर
Volume of body = V = 100 cm3
= 100 × 10-6
= 10-4m3
Weight in air W = 5 kgf
Density of liquid d = 1.8 × 103 kg/m3
(i) Upthrust due to liquid = Volume of the solid submerged × density 0
= 10-4 × 1.8 × 103 × g
= 0.18 gN
= 0.18 kgf
(ii) Weight of body in liquid = Weight of body in air - upthrust
= 5 kgf - 0.18 kgf
= 4.82 kgf
APPEARS IN
संबंधित प्रश्न
Write the density of water at 4°C in S.I. unit .
A piece of iron weighs 44.5 gf in air. If the density of iron is 8.9 × 103, find the weight of iron piece when immersed in water.
A solid lighter than water is found to weigh 7.5 gf in air. When tied to a sinker the combination is found to weigh .If the sinker alone weighs 72.5 gf in water, find R.D. of solid.
A cork cut in the form of a cylinder floats in alcohol of density 0.8 gcm-3, such that 3/4 of its length is outside alcohol. If the total length of the cylinder is 35 cm and area of cross-section 25 cm2, calculate:
(1) density of cork
(2) wt. of cork
(3) extra force required to submerge it in alcohol
When a piece of ice floating in water melts, the level of water inside the glass remains same. Explain.
A solid body weighs 2.10 N. in air. Its relative density is 8.4. How much will the body weigh if placed
(1) in water,
(2) in liquid of relative density 1.2?
Write the SI units of Weight of a body
Write the SI units of Relative density
Complete the following result:
Mass = _______ × density
