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प्रश्न
The density of ice is 0.92 g cm-3 and that of sea water is 1.025 g cm-3. Find the total volume of an iceberg which floats with its volume 800 cm3 above water.
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उत्तर
Let V be the volume of the iceberg.
Volume of iceberg above water = 800 cm3
Volume of iceberg submerged in water = v
Density of ice (ρice) = 0.92 g cm-3
Density of sea water `(ρ_"sea water")` = 1.025 gcm-3
According to the law of floatation,
`"Volume of immersed part of body"/"Total volume of body" = "Density of body"/"Density of liquid"`
`v/"V" = ρ_"ice"/ρ_"seawater"`
⇒ `v/"V" = 0.92/1.025`
⇒ `v/"V" = 0.92/1.025`
⇒ `v/"V"` = 0.8976
⇒ `v` = 0.89756 V
Now,
∴ Floating Volume of iceberg = V - `v`
⇒ 800 = V - 0.89756 V
⇒ 800 = V(1 - 0.89756)
⇒ `800/0.10244` = V
⇒ V = 7809.45 cm3 ≈ 7809.5 cm3
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