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A sinker is found to weigh 56.7 gf in water. When the sinker is tied to a cork of weight 6 gf, the combination is found to weigh 40.5 gf in water. Calculate R.D. of cork. - Physics

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प्रश्न

A sinker is found to weigh 56.7 gf in water. When the sinker is tied to a cork of weight 6 gf, the combination is found to weigh 40.5 gf in water. Calculate R.D. of cork.

योग
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उत्तर

Weight of sinker in water = 56.7 gf
Weight of cork = 6 gf
Wt. of sinker in water + Wt. of cork in air
= 56.7 + 6 = 62.7 gf …(1)
Wt. of cork in water + Wt. of sinker in water = 40.5 gf …(2)
Subtract eq. (1) from eq. (2)
Wt. of cork in air – Wt. of cork in water = 62.7 – 40.5 = 22.2 gf

∴ R.D. of cork =`"Weight of cork in air"/("wt. of cork in air - wt. of cork in water")`

`= 6/22.2 = 0.27`

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गोयल ब्रदर्स प्रकाशन A New Approach to ICSE Physics Part 1 [English] Class 9
अध्याय 5 Upthrust and Archimedes’ Principle
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