Advertisements
Advertisements
प्रश्न
A body weighs 450 gf in air and 310 gf when completely immersed in water. Find
(i) The volume of the body,
(ii) The loss in weight of the body, and
(iii) The upthrust on the body.
State the assumption made in part (i).
Advertisements
उत्तर
Weight of body in air = 450 gf
Weight of body in water = 310 gf
(i) Volume of the body = Loss in weight × density of water
= (450 - 310) × 1 [Assumption : density of water = `1 "g cm"^-3`]
= 140 `"cm"^3`
(ii) Loss in weight = Weight of body in air - Weight of body water
= (450 - 310) gf
= 140 gf
(iii) Upthrust on body = loss in weight = 140 gf
APPEARS IN
संबंधित प्रश्न
A body experiences the same buoyant force while floating in water or alcohol.
The weight of a body floating in a liquid is ........
Why does it happen?
A ship dips to a larger depth in fresh water as compared to marine water.
Differentiate between thrust and pressure.
Complete the following sentence :
Pressure is .................... in all directions about a point in a liquid.
The S.I. unit of pressure is :
What is the cause of upthrust? At which point can it be considered to act?
A piece of wood if left under water comes to the surface. Explain the reason.
A body will experience minimum upthrust when it is completely immersed in :
Is pressure a vector quantity?
