Advertisements
Advertisements
प्रश्न
A body weighs 450 gf in air and 310 gf when completely immersed in water. Find
(i) The volume of the body,
(ii) The loss in weight of the body, and
(iii) The upthrust on the body.
State the assumption made in part (i).
Advertisements
उत्तर
Weight of body in air = 450 gf
Weight of body in water = 310 gf
(i) Volume of the body = Loss in weight × density of water
= (450 - 310) × 1 [Assumption : density of water = `1 "g cm"^-3`]
= 140 `"cm"^3`
(ii) Loss in weight = Weight of body in air - Weight of body water
= (450 - 310) gf
= 140 gf
(iii) Upthrust on body = loss in weight = 140 gf
APPEARS IN
संबंधित प्रश्न
What is meant by the term ‘buoyancy’ ?
Why do we feel light on our feet when standing in a swimming pool with water up to our armpits ?
A piece of wood floats on water. The buoyant force on wood will be
For a floating body, how is its weight related to the buoyant force?
Why do sea divers need special protective suit?
State the laws of liquid pressure.
Complete the following sentence :
Pressure at a depth h in a liquid of density p is ......................
The S.I. unit of upthrust is :
Two spheres A and B, each of volume 100 cm3 is placed on water (density = 1.0 g cm−3). The sphere A is made of wood of density 0.3 g cm−3 and sphere B is made of iron of density 8.9 g cm−3.
- Find:
- The weight of each sphere, and
- The upthrust on each sphere.
- Which sphere will float? Give reason.
State whether true or false. If false, correct the statement.
The weight of fluid displaced determines the buoyant force on an object.
