Advertisements
Advertisements
Question
A body weighs 450 gf in air and 310 gf when completely immersed in water. Find
(i) The volume of the body,
(ii) The loss in weight of the body, and
(iii) The upthrust on the body.
State the assumption made in part (i).
Advertisements
Solution
Weight of body in air = 450 gf
Weight of body in water = 310 gf
(i) Volume of the body = Loss in weight × density of water
= (450 - 310) × 1 [Assumption : density of water = `1 "g cm"^-3`]
= 140 `"cm"^3`
(ii) Loss in weight = Weight of body in air - Weight of body water
= (450 - 310) gf
= 140 gf
(iii) Upthrust on body = loss in weight = 140 gf
APPEARS IN
RELATED QUESTIONS
A body experiences the same buoyant force while floating in water or alcohol.
A body experiences the same buoyant force when it floats or sinks in water.
What is the cause of buoyant force ?
Name the S.I. unit of density. How is it related to g Cm-3?
A simple U tube contains mercury to the same level in both of its arms. If water is poured to a height of 13.6 cm in one arm, how much will be the rise in mercury level in the other arm?
Given : density of mercury = 13.6 x 103 kg m-3 and density of water = 103 kg m-3.
Why is a force needed to keep a block of wood inside water?
The S.I. unit of upthrust is :
What do you mean by buoyancy?
How is thrust different from pressure?
Write about buoyant force.
