Advertisements
Advertisements
Question
Assertion: Aldehydes and ketones, both react with Tollen’s reagent to form silver mirror.
Reason: Both, aldehydes and ketones contain a carbonyl group.
Options
Assertion and reason both are correct and reason is correct explanation of assertion.
Assertion and reason both are wrong statements.
Assertion is correct statement but reason is wrong statement.
Assertion is wrong statement but reason is correct statement.
Assertion and reason both are correct statements but reasson is not correct explanation of assertion.
Advertisements
Solution
Assertion is wrong statement but reason is correct statement.
Explanation:
The silver mirror test can be used to determine Tollen's. \[\ce{[Ag(NH2)2]+ OH-}\]. Only aldehydes, not ketones, react with Tollen's reagent to create silver.
A silver mirror test is not given with this affirmative test.
The carbonyl group is present in both aldehyde and ketone.
APPEARS IN
RELATED QUESTIONS
On acid hydrolysis, propane nitrile gives.
How is carbolic acid prepared from chlorobenzene?
Predict the products of the following reactions:
Name the reagents used in the following reactions:
Show how the following compound can be converted to benzoic acid.
Ethylbenzene
Show how the following compound can be converted to benzoic acid.
Acetophenone
Predict the products formed when cyclohexanecarbaldehyde reacts with the following reagent.
Tollens’ reagent
How will you prepare the given compound from benzene? You may use any inorganic reagent and any organic reagent having not more than one carbon atom.
m-Nitrobenzoic acid
How will you bring about the following conversion in not more than two steps?
Benazaldehyde to α-Hydroxyphenylacetic acid
Name the reagents used in the following reactions:
Which is the most suitable reagent for the following conversion?
\[\begin{array}{cc}
\phantom{....................}\ce{O}\phantom{.....................................}\ce{O}\phantom{.}\\
\phantom{....................}||\phantom{......................................}||\phantom{.}\\
\phantom{}\ce{CH3 - CH = CH - CH2 - C - CH3 -> CH3 - CH = CH - CH2 - C - OH}\phantom{.}
\end{array}\]
Match the reactions given in Column I with the suitable reagents given in Column II.
| Column I (Reactions) |
Column II (Reagents) |
| (i) Benzophenone Diphenylmethane | (a) \[\ce{LiAlH4}\] |
| (ii) Benzaldehyde 1-Phenylethanol | (b) \[\ce{DIBAL-H}\] |
| (iii) Cyclohexanone Cyclohexanol | (c) \[\ce{Zn(Hg)/Conc. HCl}\] |
| (iv) Phenyl benzoate Benzaldehyde | (d) \[\ce{CH3MgBr}\] |
Match List - I with List - II.
| List - I | List - II | ||
| (a) |  \[\ce{->[CO,HCl][Anhyd. AlCl3/CuCl]}\] |
(i) | Hell-Volhard-Zelinsky reaction |
| (b) |
\[\begin{array}{cc}
\ce{O}\phantom{.................}\\ ||\phantom{.................}\\ \ce{R - C - CH3 + NaOX ->} \end{array}\] |
(ii) | Gattermann-Koch reaction |
| (c) | \[\ce{R - CH2 - OH + R'COOH ->[Conc. H2SO4]}\] | (iii) | Haloform reaction |
| (d) | \[\ce{R - CH2COOH ->[(i) X2/Red P][(ii) H2O]}\] | (iv) | Esterification |
Choose the correct answer from the options given below.
The end product Y in the sequence of reaction:
\[\ce{RX ->[CN^-] X ->[NaOH] Y}\] is:
Y is:
