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Question
As one considers orbits with higher values of n in a hydrogen atom, the electric potential energy of the atom
Options
decreases
increases
remains the same
does not increase
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Solution
increases
The electric potential energy of hydrogen atom with electron at the nth state is given by
V = - `(2xx13.6)/n^2`
As the value of n increases, the potential energy of the hydrogen atom also increases, i.e. the atom becomes less bound as n increases.
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