Advertisements
Advertisements
Question
Add:
7a2bc, –3abc2, 3a2bc, 2abc2
Advertisements
Solution
We have,
7a2bc + (–3abc2) + 3a2bc + 2abc2 = 7a2bc – 3abc2 + 3a2bc + 2abc2
= (7a2bc + 3a2bc) + (–3abc2 + 2abc2) ...[Grouping like terms]
= 10a2bc + (–abc2)
= 10a2bc – abc2
APPEARS IN
RELATED QUESTIONS
Subtract 3xy + 5yz − 7zx from 5xy − 2yz − 2zx + 10xyz.
Subtract: 6xy from − 12xy
From the sum of 4 + 3x and 5 - 4x + 2x2, subtract the sum of 3x2 - 5x and -x2 + 2x + 5.
Add the following algebraic expression:
\[\frac{3}{2}a - \frac{5}{4}b + \frac{2}{5}c, \frac{2}{3}a - \frac{7}{2}b + \frac{7}{2}c, \frac{5}{3}a + \frac{5}{2}b - \frac{5}{4}c\]
Subtract:
2a2 from − 7a2
Add:
3y2 − 10y + 16; 2y − 7
Solve the following equation.
10 = 2y + 5
Find the sum of the following expressions
7p + 6q, 5p – q, q + 16p
Find the sum of the following expressions
u + v, u – v, 2u + 5v, 2u – 5v
Multiply the following:
(ab + c), (ab + c)
