Advertisements
Advertisements
प्रश्न
Add:
7a2bc, –3abc2, 3a2bc, 2abc2
योग
Advertisements
उत्तर
We have,
7a2bc + (–3abc2) + 3a2bc + 2abc2 = 7a2bc – 3abc2 + 3a2bc + 2abc2
= (7a2bc + 3a2bc) + (–3abc2 + 2abc2) ...[Grouping like terms]
= 10a2bc + (–abc2)
= 10a2bc – abc2
shaalaa.com
क्या इस प्रश्न या उत्तर में कोई त्रुटि है?
अध्याय 7: Algebraic Expression, Identities and Factorisation - Exercise [पृष्ठ २३०]
APPEARS IN
संबंधित प्रश्न
Add: t - 8tz, 3tz - z, z - t
Add: a + b - 3, b - a + 3, a - b + 3
Add: 3p2q2 - 4pq + 5, - 10p2q2, 15 + 9pq + 7p2q2
Subtract: -x2 + 10x - 5 from 5x - 10
What should be subtracted from 2a + 8b + 10 to get - 3a + 7b + 16?
Subtract:
\[\frac{3}{2}x - \frac{5}{4}y - \frac{7}{2}z \text { from }\frac{2}{3}x + \frac{3}{2}y - \frac{4}{3}z\]
Add: 7mn, 5mn
The addition of 3mn, – 5mn, 8mn and – 4mn is
Add the following expressions:
p2 – q + r, q2 – r + p and r2 – p + q
Translate the following algebraic expression:
8(m + 5)
