Advertisements
Advertisements
प्रश्न
Add:
7a2bc, –3abc2, 3a2bc, 2abc2
योग
Advertisements
उत्तर
We have,
7a2bc + (–3abc2) + 3a2bc + 2abc2 = 7a2bc – 3abc2 + 3a2bc + 2abc2
= (7a2bc + 3a2bc) + (–3abc2 + 2abc2) ...[Grouping like terms]
= 10a2bc + (–abc2)
= 10a2bc – abc2
shaalaa.com
क्या इस प्रश्न या उत्तर में कोई त्रुटि है?
अध्याय 7: Algebraic Expression, Identities and Factorisation - Exercise [पृष्ठ २३०]
APPEARS IN
संबंधित प्रश्न
Add the following:
a − b + ab, b − c + bc, c − a + ac
Add: -7mn + 5, 12mn + 2, 9mn - 8, -2mn - 3
From the sum of 3x - y + 11 and - y - 11, subtract 3x - y - 11.
Add the following algebraic expression:
3a2b, − 4a2b, 9a2b
If \[x + \frac{1}{x} = 9,\] find the value of \[x^4 + \frac{1}{x^4} .\]
Solve the following equation.
10 = 2y + 5
If x is a natural number, then x + 1 is its predecessor
Add: −9y, 11y, 2y
Simplify: n + (m + 1) + (n + 2) + (m + 3) + (n + 4) + (m + 5)
Add the following expressions:
a2 + 3ab – bc, b2 + 3bc – ca and c2 + 3ca – ab
