Advertisements
Advertisements
प्रश्न
Add:
17a2b2 + 16c; 28c − 28a2b2
योग
Advertisements
उत्तर १
(17a2b2 + 16c) + (28c − 28a2b2)
= 17a2b2 + 16c + 28c − 28a2b2
= (17a2b2 − 28a2b2) + (16c + 28c)
= −11a2b2 + 44c
shaalaa.com
उत्तर २
17a2b2 + 16c
+ (−28a2b2 + 28c)
−11a2b2 + 44c
shaalaa.com
क्या इस प्रश्न या उत्तर में कोई त्रुटि है?
संबंधित प्रश्न
Add the following:
ab − bc, bc − ca, ca − ab
Add the following:
a − b + ab, b − c + bc, c − a + ac
Add: 14x + 10y - 12xy - 13, 18 - 7x - 10y + 8xy, 4xy
Subtract:
\[x^2 y - \frac{4}{5}x y^2 + \frac{4}{3}xy \text { from } \frac{2}{3} x^2 y + \frac{3}{2}x y^2 - \frac{1}{3}xy\]
Subtract 3x − 4y − 7z from the sum of x − 3y + 2z and − 4x + 9y − 11z.
If \[x + \frac{1}{x} = 12,\] find the value of \[x - \frac{1}{x} .\]
Add: 7x2 - 4x + 5 and 9x – 10.
The expressions 8x + 3y and 7x + 2y cannot be added
If x is a natural number, then x + 1 is its predecessor
a(b + c) = a × ____ + a × _____.
