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प्रश्न
Add:
13x2 − 12y2; 6x2 − 8y2
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उत्तर
(13x2 − 12y2) + (6x2 − 8y2)
= 13x2 − 12y2 + 6x2 − 8y2
= (13x2 + 6x2) + (−12y2 − 8y2)
= 19x2 + (−20y2)
= 19x2 − 20y2
संबंधित प्रश्न
Simplify combining like terms: (3y2 + 5y - 4) - (8y - y2 - 4)
Subtract: - 5y2 from y2
Subtract:
\[\frac{2}{3} y^3 - \frac{2}{7} y^2 - 5 \text { from }\frac{1}{3} y^3 + \frac{5}{7} y^2 + y - 2\]
Subtract:
\[\frac{ab}{7} - \frac{35}{3}bc + \frac{6}{5}ac \text { from } \frac{3}{5}bc - \frac{4}{5}ac\]
Subtract 3x − 4y − 7z from the sum of x − 3y + 2z and − 4x + 9y − 11z.
If \[x - \frac{1}{x} = 3,\] find the values of \[x^2 + \frac{1}{x^2}\] and \[x^4 + \frac{1}{x^4} .\]
If \[x + \frac{1}{x} = 9,\] find the value of \[x^4 + \frac{1}{x^4} .\]
Sum of x2 + x and y + y2 is 2x2 + 2y2.
Add the following expressions:
t – t2 – t3 – 14; 15t3 + 13 + 9t – 8t2; 12t2 – 19 – 24t and 4t – 9t2 + 19t3
Write two different algebraic expressions for the word phrase “`(1/4)` of the sum of x and 7.”
