Advertisements
Advertisements
प्रश्न
Add:
7a2bc, –3abc2, 3a2bc, 2abc2
बेरीज
Advertisements
उत्तर
We have,
7a2bc + (–3abc2) + 3a2bc + 2abc2 = 7a2bc – 3abc2 + 3a2bc + 2abc2
= (7a2bc + 3a2bc) + (–3abc2 + 2abc2) ...[Grouping like terms]
= 10a2bc + (–abc2)
= 10a2bc – abc2
shaalaa.com
या प्रश्नात किंवा उत्तरात काही त्रुटी आहे का?
पाठ 7: Algebraic Expression, Identities and Factorisation - Exercise [पृष्ठ २३०]
APPEARS IN
संबंधित प्रश्न
Add the following:
2p2q2 − 3pq + 4, 5 + 7pq − 3p2q2
Subtract 3xy + 5yz − 7zx from 5xy − 2yz − 2zx + 10xyz.
Simplify combining like terms: 21b − 32 + 7b − 20b
Add: 3mn, − 5mn, 8mn, −4mn
Add: 5m - 7n, 3n - 4m + 2, 2m - 3mn - 5
Subtract: -x2 + 10x - 5 from 5x - 10
What should be taken away from 3x2 - 4y2 + 5xy + 20 to obtain - x2 - y2 + 6xy + 20?
Add: 7x2 - 4x + 5 and 9x – 10.
Add:
5x2 – 3xy + 4y2 – 9, 7y2 + 5xy – 2x2 + 13
Add the following expressions:
x3 – x2y – xy2 – y3 and x3 – 2x2y + 3xy2 + 4y
